我正在研究一个d3项目,我正在尝试绘制一个层次结构树来向人们展示他们负责的人。基本上我可以使用A和用户B,他们每个人都可以对同一个人负责。
目前要在构建我可重复数据的可视化的JSON数据中突出显示这一点,当有2个或更多人负责同一个人时,是否可以不重复数据并使用相同的数据点?
这是我的JSfiddle示例
你会在这里看到,Raymond Reddington&唐纳德·雷斯勒(Donald Ressler)在他们的一些责任之间交叉,我正在重复看似效率低下的数据,有更好的方法,这是我的JSON。
[
{
"name" : "Company Name",
"parent" : null,
"children": [
{
"name" : "Raymond Reddington",
"parent" : "Cherry Tree Lodge",
"children" : [
{
"name" : "Debe Zuma",
"parent" : "Raymond Reddington",
},
{
"name" : "Tom Keen",
"parent" : "Raymond Reddington",
},
{
"name" : "Aram Mojtabai",
"parent" : "Raymond Reddington",
}
]
},
{
"name" : "Elizabeth Keen",
"parent" : "Cherry Tree Lodge",
"children" : [
{
"name" : "Samar Navabi",
"parent" : "Elizabeth Keen",
},
{
"name" : "Meera Malik",
"parent" : "Elizabeth Keen",
},
{
"name" : "Mr. Kaplan",
"parent" : "Elizabeth Keen",
},
{
"name" : "Reven Wright",
"parent" : "Elizabeth Keen",
}
]
},
{
"name" : "Donald Ressler",
"parent" : "Cherry Tree Lodge",
"children" : [
{
"name" : "Matius Solomon",
"parent" : "Donald Ressler",
"size" : 3938
},
{
"name" : "Peter Kotsiopulos",
"parent" : "Donal Ressler",
"size" : 3938
},
{
"name" : "Tom Keen",
"parent" : "Raymond Reddington",
"size" : 3938
},
{
"name" : "Aram Mojtabai",
"parent" : "Raymond Reddington",
"size" : 3938
}
]
},
{
"name" : "Harold Cooper",
"parent" : "Cherry Tree Lodge",
"children" : [
{
"name" : "Samar Navabi",
"parent" : "Elizabeth Keen",
"size" : 3938
},
{
"name" : "Meera Malik",
"parent" : "Elizabeth Keen",
"size" : 3938
}
]
}
]
}
答案 0 :(得分:0)
本网站详细介绍了将平面数据转换为d3 this post
所需的分层数据的方法他们也很好地解释了。正如作者所说,它最初基于http://www.d3noob.org/2014/01/tree-diagrams-in-d3js_11.html
我复制并粘贴了他们网站的示例:
var data = [
{ "name" : "Level 2: A", "parent":"Top Level" },
{ "name" : "Top Level", "parent":"null" },
{ "name" : "Son of A", "parent":"Level 2: A" },
{ "name" : "Daughter of A", "parent":"Level 2: A" },
{ "name" : "Level 2: B", "parent":"Top Level" }
];
将映射到:
var treeData = [
{
"name": "Top Level",
"parent": "null",
"children": [
{
"name": "Level 2: A",
"parent": "Top Level",
"children": [
{
"name": "Son of A",
"parent": "Level 2: A"
},
{
"name": "Daughter of A",
"parent": "Level 2: A"
}
]
},
{
"name": "Level 2: B",
"parent": "Top Level"
}
]
}
];
通过:
var dataMap = data.reduce(function(map, node) {
map[node.name] = node;
return map;
}, {});
var treeData = [];
data.forEach(function(node) {
// add to parent
var parent = dataMap[node.parent];
if (parent) {
// create child array if it doesn't exist
(parent.children || (parent.children = []))
// add node to child array
.push(node);
} else {
// parent is null or missing
treeData.push(node);
}
});
您可以进一步扩展以替换Ids并使用第二个规范化数组进行查找:
[{
"id": 0,
"name": "Cherry Tree Lodge"
},{
"id": 1,
"name": "Tom Keen"
},{
"id": 2,
"name": "Debe Zuma"
}]
另请注意,您的json数据并非严格有效,您还有额外的逗号。