Question

在routes.py中，我尝试过以下代码（不是正则表达式专家），并打算在url_arg中传递http / https链接，例如http://google.com或https://google.com。

r'/some_api/<url_arg:.*>'

以下是localhost的错误：8080 / some_api / https://google.com或localhost：8080 / some_api / http://google.com

Traceback (most recent call last):
  File "/google-cloud-sdk/platform/google_appengine/lib/cherrypy/cherrypy/wsgiserver/wsgiserver2.py", line 1292, in communicate
    req.parse_request()
  File "/google-cloud-sdk/platform/google_appengine/lib/cherrypy/cherrypy/wsgiserver/wsgiserver2.py", line 580, in parse_request
    success = self.read_request_line()
  File "/google-cloud-sdk/platform/google_appengine/lib/cherrypy/cherrypy/wsgiserver/wsgiserver2.py", line 643, in read_request_line
    scheme, authority, path = self.parse_request_uri(uri)
  File "/google-cloud-sdk/platform/google_appengine/lib/cherrypy/cherrypy/wsgiserver/wsgiserver2.py", line 805, in parse_request_uri
    authority, path = remainder.split(FORWARD_SLASH, 1)
ValueError: need more than 1 value to unpack

Answer 1

看起来这是cherrypy中的错误，由应用程序引擎的devappserver2使用。详细信息：https://code.google.com/archive/p/appengine-devappserver2-experiment/issues/69

（我有同样的问题，目前还没有好的解决方法或解决方法。）

正则表达式在webapp2（Python）中提取URL参数，如URL＆＃39; s？

1 个答案: