Question

我正在使用OSMC和同一Pi上的网络服务器运行Raspberry Pi。

我做了一个python脚本，它获取了cpu temp，usage，memory等。当我使用sudo python state.py执行脚本时，它可以工作，它获取值并将它们写入txt文件。

我希望脚本在启动时运行，所以我创建了一个crontab：

@reboot sudo python /home/osmc/python/state.py &

这样可行，但它会将CPU统计信息写入文件，只写入内存和磁盘统计信息。

我的python脚本如下所示：

#!/usr/bin/python
import os
import sys
import commands
import time

# Return CPU temperature as a character string                                      
def getCPUtemperature():
    res = os.popen('vcgencmd measure_temp').readline()
    return(res.replace("temp=","").replace("'C\n",""))

# Return RAM information (unit=kb) in a list                                        
# Index 0: total RAM                                                                
# Index 1: used RAM                                                                 
# Index 2: free RAM                                                                 
def getRAMinfo():
    p = os.popen('free')
    i = 0
    while 1:
        i = i + 1
        line = p.readline()
        if i==2:
            return(line.split()[1:4])

# Return % of CPU used by user as a character string                                
def getCPUuse():
    return(str(os.popen("top -n1 | awk '/Cpu\(s\):/ {print $2}'").readline().strip(\
)))

# Return information about disk space as a list (unit included)                     
# Index 0: total disk space                                                         
# Index 1: used disk space                                                          
# Index 2: remaining disk space                                                     
# Index 3: percentage of disk used                                                  
def getDiskSpace():
    p = os.popen("df -h /")
    i = 0
    while 1:
        i = i +1
        line = p.readline()
        if i==2:
            return(line.split()[1:5])
while True:
        # CPU informatiom
        CPU_temp = getCPUtemperature()
        CPU_usage = getCPUuse()

        # RAM information
        # Output is in kb, here I convert it in Mb for readability
        RAM_stats = getRAMinfo()
        RAM_total = round(int(RAM_stats[0]) / 1000,1)
        RAM_used = round(int(RAM_stats[1]) / 1000,1)
        RAM_free = round(int(RAM_stats[2]) / 1000,1)

        # Disk information
        DISK_stats = getDiskSpace()
        DISK_total = DISK_stats[0]
        DISK_free = DISK_stats[1]
        DISK_perc = DISK_stats[3]

        starttime = time.time()

        file = open("/var/www/html/rspi_state.txt", "w")


        file.write(CPU_temp + "\n")
        file.write(CPU_usage + "\n")
        file.write(DISK_stats[1] + "\n")
        file.write(DISK_stats[0] + "\n")
        file.write(DISK_stats[3] + "\n")
        file.write(str(RAM_total) + "\n")
        file.write(str(RAM_free) + "\n")
        file.close()
        print "CPU TEMP: " + CPU_temp
        time.sleep(9.0 - ((time.time() - starttime) % 9.0))

有什么理由说它只将一些数据写入文本文件？任何帮助深表感谢！

Answer 1

您可以通过编写专注于问题的脚本来诊断问题。这个将记录从系统调用返回的所有信息。我认为my_popen的修改版本会检查错误......或subprocess中的错误检查调用之一是个好主意。我自己做了很多系统调用，并为Popen提供了一个复杂的包装器，可以记录并执行各种奇特的操作。以与常规脚本相同的方式运行此脚本，看看会发生什么：

import subprocess as subp

def my_popen(cmd, file):
    file.write('cmd: {}\n'.format(cmd))
    proc = subp.Popen(cmd, shell=True, stdout=subp.PIPE, stderr=subp.PIPE)
    out, err = proc.communicate()
    print('return code: {}\n'.format(proc.returncode))
    print('out: {}\n'.format(out))
    print('err: {}\n'.format(err))
    print('------\n')
    return out

with file = open("/var/www/html/test_state.txt", "w") as file:
    my_popen('vcgencmd measure_temp', file)
    my_popen("top -n1 | awk '/Cpu\(s\):/ {print $2}'", file)

写入文件

1 个答案: