Question

我觉得自己很傻但是我无法弄清楚如何在我的YQL RSS Feed中添加限制我在这里是jsfiddle - 我只想展示最后2个（最近的）博客帖子

＆＃13;

YUI().use('node', 'gallery-yql', function(Y) {
  new Y.yql('select * from rss where url="http://caremonkeys.co.uk/feed/"',
  function(r) {
    if (r.query) {
      if (r.query.results) {
         var res = Y.one('#results'), content = '<ul><li></li>';
         Y.each(r.query.results.item, 
            function(v) {
              var the_link=v.link;
              var the_title=v.title;
              var the_desc=v.description;
              var the_image=v.image;
              var the_cat=v.category;
content += "<li class="+the_cat+"><a href="+the_link+">"+the_title+"</a>"+the_desc+"<img src="+the_image+"></li>";
                });
         content += "</ul>";
         res.setContent(content);
}}});});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="results">Loading...</div>

＆＃13;

对此的任何帮助将不胜感激！

Answer 1

Try this,change no_items to wordpress limit,

YUI().use('node', 'gallery-yql', function(Y) {
  new Y.yql('select * from rss where url="http://caremonkeys.co.uk/feed/"',
  function(r) {
    if (r.query) {
      if (r.query.results) {
         var res = Y.one('#results'), content = '<ul><li></li>';

         //
           var no_items= 2;
           var item = r.query.results.item;
           for(var i=0;i<no_items;i++){  

               var title = item[i].title;  
               var link =  item[i].link;  
               var desc =  item[i].description;  
               var the_cat = item[i].category;
               content += "<li class="+the_cat+"><a href="+the_link+">"+the_title+"</a>"+the_desc+"<img src="+the_image+"></li>";

           }

         //
         content += "</ul>";
         res.setContent(content);
}}});});

YQL rss来自wordpress set limit

1 个答案: