我有三个表，即家庭（PK id_family和FK id_husband），丈夫（PK id_husband）和house（PK id_husband）。因为丈夫与房子有关。然后桌子的丈夫与家庭桌子有关。
我已经制作了一个更新表格来形成房子以查看下面的参考资料。在我在表格中更新逻辑之前，表格中的字段将更新丈夫，在平均字段即'status_husband'。因为它已成功地做到了。 然后，当进程保存在actionUpdate中时，在更新表单上的输入时，将自动加载到族表中的字段。 Fieldnya id_family，id_husband和status_family。因为它管理得很好，我使用了形式复杂的概念。
我想在更新中并且将完成所有这一切的过程时，有验证要求表单中的所有字段更新所有“省”和“城市”必须用值'example1填充'全部。因此，如果不处理一个差异。也许有人可以帮助我，谢谢
表单更新中的代码视图..
<?php
use yii\helpers\Html;
use yii\bootstrap\ActiveForm;
use yii\widgets\Pjax;
use yii\bootstrap\Modal;
use yii\helpers\Url;
use yii\db\ActiveRecord;
use yii\helpers\ArrayHelper;
use app\models\Husband;
use kartik\widgets\Select2;
?>
<h1 align="center">Form Ubah House</h2>
<?php
echo " ";
echo " ";
?>
<?php $form = ActiveForm::begin([
'layout' => 'horizontal',
'enableAjaxValidation' => false,
'id' => 'update-form',
]);
?>
<?php
$data = ArrayHelper::map(Husband::find()->all(), 'id_husband', 'name_husband');
echo $form->field($house, 'id_husband')->widget(Select2::classname(), [
'data' => $data,
'model' => $house,
'language' => 'id',
'disabled' => true,
'options' => ['placeholder' => 'Choose..'],
'pluginOptions' => [
'allowClear' => false,
'width' => '300px',
],
])->label('Name husband');
?>
<?php
echo $form->field($house, 'province')->widget(Select2::classname(), [
'model' => $house,
'hideSearch' => true,
'data' => ['example1' => "Example1", 'example2' => "Example2"],
'language' => 'id',
'options' => [
'placeholder' => 'Choose..',
'id' => 'province',
],
'pluginOptions' => [
'allowClear' => false,
'width' => '380px',
],
])->label('Province');
?>
<?php
echo $form->field($house, 'city')->widget(Select2::classname(), [
'model' => $house,
'hideSearch' => true,
'data' => ['example1' => "Example1", 'example2' => "Example2"],
'language' => 'id',
'disabled' => true,
'options' => [
'placeholder' => 'Choose..',
'id' => 'city',
],
'pluginOptions' => [
'allowClear' => false,
'width' => '380px',
],
])->label('City');
?>
<?= $form->field($family, 'id_family')->hiddenInput(['readOnly' => true, 'style' => 'width:100px'])->label(false); ?>
<?php
$family->id_husband = $house->id_husband;
?>
<?= $form->field($family, 'id_husband')->hiddenInput(['style' => 'width:100px'], ['disabled' => true])->label(false); ?>
<?= $form->field($family, 'status_house')->hiddenInput(['style' => 'width:380px', 'value'=>'Tetap'], ['disabled' => true])->label(false); ?>
<div class="form-group">
<div class="col-sm-offset-4">
<?= Html::submitButton('Edit', ['class' => 'btn btn-primary']) ?>
<?php
echo " ";
echo " ";
echo Html::a('Exit', ['index'],[
'class'=>'btn btn-success',
'onclick' =>'$("#houseModal").modal("hide");
return false;'
]);
?>
<?php ActiveForm::end();?>
HouseController中的代码actionUpdate
public function actionUpdate($id)
{
$house = House::findOne($id);
if (!$house) {
throw new NotFoundHttpException("The house was not found.");
}
$family = new Family();
if (!$family) {
throw new NotFoundHttpException("The family was not found.");
}
if ($house->load(Yii::$app->request->post()) && $family->load(Yii::$app->request->post())) {
$isValid = $house->validate();
$isValid = $family->validate() && $isValid;
if ($isValid) {
// Code for update field status_husband in table Husband
$husband = Husband::findOne($id);
$husband->status_husband = 'Meninggal';
$husband->save();
// Code for update field in table house
$house->save(false);
// Code for insert in table family
$family->save(false);
Yii::$app->session->setFlash('success', 'Success!');
return $this->redirect(['index']);
return $this->refresh();
}
} else {
if (Yii::$app->request->isAjax) {
return $this->renderAjax('update', [
'house' => $house,
'family' => $family]);
} else {
return $this->render('update', [
'house' => $house,
'family' => $family]);
}
}
}
答案 0 :(得分：0)
如果使用相同的数据库连接组件将所有3个模型保存到同一个数据库，则可以使用数据库事务：
public function actionUpdate($id)
{
$house = House::findOne($id);
if (!$house) {
throw new NotFoundHttpException("The house was not found.");
}
$family = new Family();
if (!$family) {
throw new NotFoundHttpException("The family was not found.");
}
$husband = Husband::findOne($id); // Why use the same $id that you use to find $house?
if (!$husband) {
throw new NotFoundHttpException("The husband was not found.");
}
$post = Yii::$app->request->post();
// we get the database component used by the House model class and begin a transaction
$transaction = House::getDb()->beginTransaction();
try {
if ($house->load($post) && $family->load($post)) {
// Try to save $house model
if(!$house->save()) {
// If we get a validation error then we will throw an exception and execute the code in catch
throw new \Exception('House Validation Error');
}
// Try to save $family model
if(!$family->save()) {
// If we get a validation error then we will throw an exception and execute the code in catch
throw new \Exception('Family Validation Error');
}
// Set new status for $husband
$husband->status_husband = 'Meninggal';
// Try to save $husband model
if(!$husband->save()) {
// If we get a validation error then we will throw an exception and execute the code in catch
throw new \Exception('Husband Validation Error');
}
// we commit the database changes after every model has been saved succesfully
$transaction->commit();
Yii::$app->session->setFlash('success', 'Success!');
return $this->redirect(['index']);
// This doesn't get called ever, so why have it here?
// return $this->refresh();
} else {
throw new \Exception('Load Error');
}
} catch(\Exception $e) {
// If we catch any exception we rollback the transaction, reverting all the changes made during the transaction
$transaction->rollback();
}
if (Yii::$app->request->isAjax) {
return $this->renderAjax('update', [
'house' => $house,
'family' => $family]);
} else {
return $this->render('update', [
'house' => $house,
'family' => $family]);
}
}