如何在ComboBox中显示我的所有DataSet

时间:2016-11-01 09:01:23

标签: c# sql-server visual-studio listview combobox

如何使用项目中的所有数据集填充我的ComboBox

我的代码

 foreach (DataTable table in DataSet.Tables)
            {
                foreach (DataRow row in table.Rows)
                {
                    foreach (DataColumn column in table.Columns)
                    {
                        object item = row[column];

                    }
                }
                comboBox1.Items.Add(table.TableName);
            }

2 个答案:

答案 0 :(得分:0)

您需要仅使用tableNames填充组合框。

foreach (DataTable table in DataSet.Tables)
        {
            comboBox1.Items.Add(table.TableName);
        }

然后你需要编写组合框的Select事件,它可能看起来像这样。

private void comboBox1_SelectedIndexChanged(object sender, System.EventArgs e)
{
    //fill listview with items that belong to the combobox.SelectedItem
    //since you filled the combobox with table.TableName, the name will be in .SelectedItem
}

不要忘记

this.comboBox1.SelectedIndexChanged += new System.EventHandler(comboBox1_SelectedIndexChanged);

答案 1 :(得分:0)

修改您的查询以获取sql命令结果中的所有数据,例如

        string connetionString = null;
        SqlConnection connection;
        SqlCommand command;
        SqlDataAdapter adapter = new SqlDataAdapter();
        DataSet ds = new DataSet();
        int i = 0;
        string sql = null;
        connetionString = "Data Source=.;Initial Catalog=DatabaseName;User ID=UserName;Password=Password";
        sql = "select au_id,au_lname from authors";
        connection = new SqlConnection(connetionString);
        try
        {
            connection.Open();
            command = new SqlCommand(sql, connection);
            adapter.SelectCommand = command;
            adapter.Fill(ds);
            adapter.Dispose();
            command.Dispose();
            connection.Close();
            comboBox1.DataSource = ds.Tables[0];
            comboBox1.ValueMember = "au_id";
            comboBox1.DisplayMember = "au_lname";
        }
        catch (Exception ex)
        {
            MessageBox.Show("Can not open connection ! ");
        }