错误＃1052。帮我找到MySQL查询中的错误

Question

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我需要找到捐赠超过三次的捐赠者。这就是我到目前为止所拥有的

 select DONOR.DONOR_LNAME as last_name, DONOR.DONOR_FNAME as first_name,    count(GIFT.AMOUNT)as NUM_PAYMENTS
from DONOR join GIFT on DONOR.DONOR_NO= GIFT.DONOR_NO 
group by DONOR_NO 
having count(AMOUNT) >=3

Answer 1

您需要在使用Table Aliases AND GROUP BY时指定HAVING。

试试这个：

SELECT DONOR.DONOR_LNAME as last_name, DONOR.DONOR_FNAME as first_name, COUNT(GIFT.AMOUNT) as NUM_PAYMENTS
FROM DONOR 
INNER JOIN GIFT ON DONOR.DONOR_NO = GIFT.DONOR_NO 
GROUP BY DONOR.DONOR_NO 
HAVING COUNT(GIFT.AMOUNT) >= 3