Question

我有一个这样的课程：

class AuthController extends Controller
{
    use AuthenticatesAndRegistersUsers, ThrottlesLogins;

    // I need to put a if() in here

    protected $redirectTo = '/home';

    public function __construct()
    {
        $this->middleware($this->guestMiddleware(), ['except' => 'logout']);
    }

    // there is some other methods in here

}

正如我在上面的代码中所评论的那样（// I need to put a if() in here），我需要比较其中的内容并将结果用作$redirectTo变量的值。

但PHP不允许我这样做。我的意思是，我想要这样的事情：

class AuthController extends Controller
{
    use AuthenticatesAndRegistersUsers, ThrottlesLogins;

    if ( Lang::getLocale() == 'en' ){
        $lang = '/en';
    } else {
        $lang = '/fa';
    }

    protected $redirectTo = '/home'.$lang;

    public function __construct()
    {
        $this->middleware($this->guestMiddleware(), ['except' => 'logout']);
    }

    // there is some other methods in here

}

正如我所说，php不允许我这样做^。我怎么能这样做？

编辑：我不能将if语句放入__construct()方法。由于setLocale()尚未设置，getLocale()始终返回默认语言（即fa）。无论如何，我需要将{if}语句放在__construct()之外。有什么建议吗？

Answer 1

你可以尝试这个：

class AuthController extends Controller
{
    use AuthenticatesAndRegistersUsers, ThrottlesLogins;

protected $lang='';
protected $redirectTo='';


    public function __construct()
    {
    if ( Lang::getLocale() == 'en' ){
        $this->$lang = '/en';
    } else {
        $this->$lang = '/fa';
    }

    $this->$redirectTo= '/home'.$lang;

        $this->middleware($this->guestMiddleware(), ['except' => 'logout']);
    }

    // there is some other methods in here

}

Answer 2

将您的逻辑添加到构造函数：

class AuthController extends Controller
{
    use AuthenticatesAndRegistersUsers, ThrottlesLogins;

    protected $redirectTo;

    public function __construct()
    {
        if ( Lang::getLocale() == 'en' ){
            $lang = '/en';
        } else {
            $lang = '/fa';
        }
        $this->redirectTo = '/home'.$lang;

        $this->middleware($this->guestMiddleware(), ['except' => 'logout']);
    }

    // there is some other methods in here

}

<强>更新

类代码只是类的定义。它不以任何方式执行。只有在显式调用它们时才能执行类方法。

类不能除属性，常量或方法之外的任何内容。

如果您需要执行某些操作 - 创建类方法。 没有其他方式。

如果您需要在调用$this->redirectTo后设置setLocale()，请在此调用后创建类的实例：

Lang::setLocale();
$ac = new AuthController();

或者在班级中创建一个特殊方法，用于检查和设置$this->redirectTo：

$ac = new AuthController();
Lang::setLocale();
$ac->setRedirectTo();

setRedirectTo()类似于：

public function setRedirectTo()
{
    if ( Lang::getLocale() == 'en' ){
        $lang = '/en';
    } else {
        $lang = '/fa';
    }
    $this->redirectTo = '/home'.$lang;
}

Answer 3

按照下面的说法：

class AuthController extends Controller
{
    use AuthenticatesAndRegistersUsers, ThrottlesLogins;

    protected $redirectTo;
    protected $lang;

    public function __construct()
    {
        if ( Lang::getLocale() == 'en' ){
            $this->lang = '/en';
        } else {
            $this->lang = '/fa';
        }
        $this->redirectTo = '/home'.$this->lang;

        $this->middleware($this->guestMiddleware(), ['except' => 'logout']);
    }

    // there is some other methods in here

}

如何在课堂上写一个if语句？

3 个答案: