Question

在matplotlib中我有：

cmap = plt.cm.RdYlBu_r
colors = cmap(np.linspace(0,1, len(patches)))
collection = PatchCollection(patches, alpha=.3, 
                             facecolor=colors, linestyle='solid')

它给了我想要的东西，除了边框继承了“alpha”属性。如何绘制具有深色边框但透明面部颜色的多边形？

Answer 1

作为旁路解决方案，您可以保留构成多边形的点，并绘制连接点的线，如下面的代码所示：

import matplotlib
import numpy,matplotlib.pyplot as plt
from matplotlib.patches import Polygon
from matplotlib.collections import PatchCollection
fig = plt.figure()
axe = fig.add_subplot(111)
polyval = numpy.random.rand(4,2) # Create the sequence of 4 2D points
patches = [Polygon(polyval,True)]
p = PatchCollection(patches,cmap=matplotlib.cm.jet,alpha=0.3)
p.set_array(100.*numpy.random.rand(1)) # Set a random color on jet map
axe.add_collection(p) 
fig.colorbar(p)
fig.show()
for patch in patches:
   axe.add_patch(Polygon(patch.get_xy(),closed=True,ec='k',lw=3,fill=False)) #draw the contours
fig.canvas.draw()

如何绘制带有深色边框但透明面部颜色的多边形？

1 个答案: