我是SQLAlchemy的新手。我有这个型号:
class AssociationUserClub(db.Model):
user_id = db.Column(db.Integer, db.ForeignKey('user.id'), primary_key=True)
club_id = db.Column(db.Integer, db.ForeignKey('club.id'), primary_key=True)
roleClub = db.Column( db.String(50) , nullable = False, server_default = "member" )
club = db.relationship("Club", back_populates="members")
user = db.relationship("User", back_populates="clubs")
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(200), unique=True)
clubs = db.relationship("AssociationUserClub", back_populates="user")
class Club(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column( db.String(255), unique = True, nullable = False )
members = db.relationship("AssociationUserClub", back_populates="club")
我想要一个用户在他所属的所有俱乐部中知道的所有用户的列表。
我尝试这个,但我找不到正确的答案:
User.query.filter( User.clubs.any( xxxx) ).all()
非常感谢
答案 0 :(得分:0)
如果我正确理解你的问题就会有这样的工作吗?
#get all users
users = User.query.all()
# for each user, look at the list of clubs they are in, and generate the list of the club
for user in users:
clubs = user.clubs
for club in clubs:
# friends are = members of the club, if that member is not the user
# Ill use List comprehension for that.
friends = [member for member in club.members if member.user_id != user.id]
# edit, if you want to remember the club they are associated with
friends = dict([(member.club_id, member) for member in club.members if member.user_id != user.id])