Question

在laravel 5.3上使用SqliteDriver

表cpjobs

...
$table->timestamp('created_at')->nullable(false);  // saved data unixtime
$table->timestamp('delayed_at')->nullable(true);  // saved data unixtime
...


| id  | delayed_at | start_at    |
|-----| ---------- | ----------- |
| 2   | null       | 1477912725  |
| 3   | 1478007928 | null        |
| 4   | null       | null        |

如果在修补程序上运行

Cpjob::where('delayed_at', '>', '1478007902')->first();
    => App\Cpjob {#694
         id: "11",
         type: "backup",
         created_at: "1477911786",
         delayed_at: "1478007928",
       }

但如果为delayed_at＆gt;运行复合体now和start_at null，返回空结果，必须返回id为4的行

 Cpjob::where([['delayed_at', '<', '1477912725'],['start_at', null]])->first();
=> null

如果生成SQL ...

>>> Cpjob::where([['delayed_at', '<', '1478007734'],['start_at', null]])->toSql();
=> "select * from "cpjobs" where ("delayed_at" < ? and "start_at" is null)"

我已尝试过几种方式来发送时间，unix时间戳，碳，但所有，产生相同的＆lt;吗

Answer 1

您可以尝试使用whereNull()：

Cpjob::where(fuction($q) {
        $q->where('delayed_at', '<', '1477912725')
          ->orWhereNull('delayed_at');
      })
      ->whereNull('start_at')
      ->first();

Answer 2

好的，谢谢你的提示。

创建我的本地范围

应用程序/ Cpjob.php

public function scopeFirstJob($query,$unixTime)
{
   return $query->whereNull('start_at')->where(function ($q) use ($unixTime) {
       $q->where('delayed_at', '<', $unixTime)->orWhereNull('delayed_at');
   })->first();
}

致电我的命令

$job = Cpjob::firstJob($unixtime)

选择时间戳值为null无效的位置

2 个答案: