如何使用多个CASE语句优化SELECT查询？

Question

在双人游戏中，PostgreSQL based game最常被调用的语句是SELECT查询返回用户正在玩的游戏列表：

（请原谅屏幕截图中的非拉丁字母）

CREATE OR REPLACE FUNCTION words_get_games(in_uid integer)
        RETURNS TABLE (
                out_gid integer, 
                out_created integer,
                out_finished integer,
                out_letters varchar[15][15],
                out_values integer[15][15],
                out_bid integer,
                out_last_tiles jsonb,
                out_last_score integer,
                out_player1 integer,
                out_player2 integer,
                out_played1 integer,
                out_played2 integer,
                out_hand1 text,
                out_hand2 text,
                out_score1 integer,
                out_score2 integer,
                out_female1 integer,
                out_female2 integer,
                out_given1 varchar,
                out_given2 varchar,
                out_photo1 varchar,
                out_photo2 varchar,
                out_place1 varchar,
                out_place2 varchar
        ) AS
$func$
    SELECT 
        g.gid,
        EXTRACT(EPOCH FROM g.created)::int,
        EXTRACT(EPOCH FROM g.finished)::int,
        g.letters,
        g.values,
        g.bid,
        m.tiles,
        m.score,
        /* HOW TO OPTIMIZE THE FOLLOWING CASE STATEMENTS? */
        CASE WHEN g.player1 = in_uid THEN g.player1 ELSE g.player2 END,
        CASE WHEN g.player1 = in_uid THEN g.player2 ELSE g.player1 END,
        CASE WHEN g.player1 = in_uid THEN g.score1 ELSE g.score2 END,
        CASE WHEN g.player1 = in_uid THEN g.score2 ELSE g.score1 END,
        CASE WHEN g.player1 = in_uid THEN s1.female ELSE s2.female END,
        CASE WHEN g.player1 = in_uid THEN s2.female ELSE s1.female END,
        CASE WHEN g.player1 = in_uid THEN s1.given ELSE s2.given END,
        CASE WHEN g.player1 = in_uid THEN s2.given ELSE s1.given END,
        CASE WHEN g.player1 = in_uid THEN s1.photo ELSE s2.photo END,
        CASE WHEN g.player1 = in_uid THEN s2.photo ELSE s1.photo END,
        CASE WHEN g.player1 = in_uid THEN s1.place ELSE s2.place END,
        CASE WHEN g.player1 = in_uid THEN s2.place ELSE s1.place END,
        EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played1 ELSE g.played2 END)::int,
        EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played2 ELSE g.played1 END)::int,
        ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand1 ELSE g.hand2 END, ''),
        REGEXP_REPLACE(ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand2 ELSE g.hand1 END, ''), '.', '?', 'g'),
    FROM words_games g 
        LEFT JOIN words_moves m ON m.gid = g.gid
        -- find move record with the most recent timestamp
        AND NOT EXISTS (SELECT 1
            FROM words_moves m2 
            WHERE m2.gid = m.gid
            AND m2.played > m.played)
    LEFT JOIN words_social s1 ON s1.uid = g.player1
        -- find social record with the most recent timestamp
        AND NOT EXISTS (SELECT 1
            FROM words_social s 
            WHERE s1.uid = s.uid
            AND s.stamp > s1.stamp)
    LEFT JOIN words_social s2 ON s2.uid = g.player2
        -- find social record with the most recent timestamp
        AND NOT EXISTS (SELECT 1
            FROM words_social s 
            WHERE s2.uid = s.uid
            AND s.stamp > s2.stamp)
    WHERE in_uid IN (g.player1, g.player2)
    AND (g.finished IS NULL OR g.finished > CURRENT_TIMESTAMP - INTERVAL '1 day');

$func$ LANGUAGE sql;

正如您在上面的自定义SQL函数中看到的那样，为了始终将用户数据作为player1，given1，score1返回，我使用了大量的CASE语句（以便获取）可以在需要时交换列）：

    CASE WHEN g.player1 = in_uid THEN g.score1 ELSE g.score2 END,

我的问题是：如果可以优化上面的SELECT查询（不用切换到较慢的PL / pgSQL）？

更新

the mailing list的Geoff提供了一个很好的建议，即在加入时已使用CASE：

SELECT 
        g.gid,
        EXTRACT(EPOCH FROM g.created)::int,
        EXTRACT(EPOCH FROM g.finished)::int,
        g.letters,
        g.values,
        g.bid,
        m.tiles,
        m.score,
        CASE WHEN g.player1 = in_uid THEN g.player1 ELSE g.player2 END,
        CASE WHEN g.player1 = in_uid THEN g.player2 ELSE g.player1 END,
        CASE WHEN g.player1 = in_uid THEN g.score1 ELSE g.score2 END,
        CASE WHEN g.player1 = in_uid THEN g.score2 ELSE g.score1 END,
        s1.female,
        s2.female,
        s1.given,
        s2.given,
        s1.photo,
        s2.photo,
        s1.place,
        s2.place,
        EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played1 ELSE g.played2 END)::int,
        EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played2 ELSE g.played1 END)::int,
        ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand1 ELSE g.hand2 END, ''),
        REGEXP_REPLACE(ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand2 ELSE g.hand1 END, ''), '.', '?', 'g')
FROM words_games g 
LEFT JOIN words_moves m ON m.gid = g.gid
        -- find move record with the most recent timestamp
        AND NOT EXISTS (SELECT 1
                FROM words_moves m2 
                WHERE m2.gid = m.gid
                AND m2.played > m.played)
LEFT JOIN words_social s1 ON s1.uid = in_uid
        -- find social record with the most recent timestamp
        AND NOT EXISTS (SELECT 1
                FROM words_social s 
                WHERE s1.uid = s.uid
                AND s.stamp > s1.stamp)
LEFT JOIN words_social s2 ON s2.uid = (CASE WHEN g.player1 = in_uid THEN g.player2 ELSE g.player1 END)
        -- find social record with the most recent timestamp
        AND NOT EXISTS (SELECT 1
                FROM words_social s 
                WHERE s2.uid = s.uid
                AND s.stamp > s2.stamp)
WHERE in_uid IN (g.player1, g.player2)
AND (g.finished IS NULL OR g.finished > CURRENT_TIMESTAMP - INTERVAL '1 day');

Answer 1

lateral和distinct on（IMO）有助于提高可读性。 distinct on也会对性能产生影响，尽管我无法猜测是正还是负。

select
    g.gid,
    extract(epoch from g.created)::int created,
    extract(epoch from g.finished)::int finished,
    g.letters,
    g.values,
    g.bid,
    m.tiles,
    m.score,
    r.*
from
    words_games g
    left join (
        select distinct on (gid, played) *
        from words_moves
        order by gid, played desc
    ) words_moves m on m.gid = g.gid
    left join (
        select distinct on (uid, stamp) *
        from words_social
        order by uid, stamp desc
    ) words_social s1 on s1.uid = g.player1
    left join (
        select distinct on (uid, stamp) *
        from words_social
        order by uid, stamp desc
    ) words_social s2 on s2.uid = g.player2
    cross join lateral (
        select
            g.player1, g.player2,
            extract(epoch from g.player1)::int, extract(epoch from g.player2)::int,
            array_to_string(g.hand1, ''),
            regexp_replace(array_to_string(g.hand2, ''), '.', '?', 'g'),
            g.score1, g.score2,
            s1.female, s2.female,
            s1.given, s2.given,
            s1.photo, s2.photo,
            s1.place, s2.place
        where g.player1 = in_uid
        union all
        select
            g.player2, g.player1,
            extract(epoch from g.player2)::int, extract(epoch from g.player1)::int,
            array_to_string(g.hand2, ''),
            regexp_replace(array_to_string(g.hand1, ''), '.', '?', 'g'),
            g.score2, g.score1,
            s2.female, s1.female,
            s2.given, s1.given,
            s2.photo, s1.photo,
            s2.place, s1.place
        where g.player1 != in_uid
    ) r
where
    in_uid in (g.player1, g.player2)
    and (g.finished is null or g.finished > current_timestamp - interval '1 day')

Answer 2

由于您担心许多案例陈述并且它始终是相同的条件，您可以将此条件拉出并且两个选择，例如

select ...
       g.player1, g.player2,
       extract(epoch from g.played1)::int, extract(epoch from g.played2)::int,
       ...
       g.score1, g.score2,
       ...

和另一个（相同）选择列交换

select ...
       g.player2, g.player1,
       extract(epoch from g.played2)::int, extract(epoch from g.played1)::int,
       ...
       g.score2, g.score1,
       ...

虽然@joop和@jarlh已经质疑，但首先测试一下，如果这确实是一个性能问题。