Question

我正在编写一些读取XML模板的PHP代码，并用PHP中的数组中的数据替换模板中的某些值。目前，当执行代码时，它将为循环的每次迭代输出一个文件，每个迭代都替换了正确的值。

我面临的问题是尝试将每个输出都放到同一个XML文档上，而不是每个输出一个。以下是目前的代码;

<?

$filename = 'MYDRIVE\XML_TEMPLATE2.xml';
$contents = file_get_contents($filename); 

$emaillist = array(array('fname'            => 'Brad',
                         'lname'            => 'BoBo',
                         'recipient'        => 'bbobo@gmail.com'),  

                   array('fname'            => 'Josh',
                         'lname'            => 'Jojo',
                         'recipient'        => 'jjojo@gmail.com'),

                   array('fname'            => 'Sam',
                         'lname'            => 'Soso',
                         'recipient'        => 'ssoso@gmail.com'),

                   array('fname'            => 'Dave',
                         'lname'            => 'Dojo',
                         'recipient'        => 'ddojo@hotmail.com'));

foreach ($emaillist as &$person) 
{

    $fname      = $person['fname'];
    $lname      = $person['lname'];
    $recipient  = $person['recipient'];
    $todaysdate = date("F j, Y, g:i a"); 

    $find       = array("[[firstname]]",
                        "[[lastname]]",
                        "[[recipient]]",
                        "[[todaysdate]]");

    $replace    = array($fname,
                        $lname,
                        $recipient,
                        $todaysdate);

    $new        = str_replace($find,
                              $replace,
                              $contents);

    // This will open/ create the file if non-existent.

    $handle      = fopen("MYDRIVE/tempname.xml", "w+");

    $filename    = 'MYDRIVE/tempname.xml';
    $filecontent = $new;

    if (is_writable($filename)) 
    { 
        print "<b>Data added to file:</b>";
        print "<br>";
        print "<br>";

        if (!$handle = fopen($filename, 'a')) 
        {
             print "Cannot open file ($filename)";
             exit;
        }

        // Adds $filecontent to file.

        if (fwrite($handle, $filecontent) === FALSE) 
        {
            print "Cannot write to file ($filename)";
            exit;
        }

        print "Success! <br><br> ($filecontent) <br><br> was added to ($filename)";

        fclose($handle);

    } 
    else 
    {
        print "<b>Error:</b>";
        print "The file $filename is not writable";
        exit();
    }

    // Generate file name for use.

    $filenamegen = date("d_h_i_s") . "_" . $person['recipient'];

    if (rename ("MYDRIVE/tempname.xml", "MYDRIVE/" . $filenamegen . ".xml"))
    { 
        print "File successfully saved as : $filenamegen";
        print "<br><br>";
    }
    else
    {
        print "Error renaming file.";
        exit();
    }

print "</div>";

}

?>

执行上述代码时，会创建4个XML文档，并为每个数据记录正确替换变量。

我面临的问题是尝试将所有数据放入单个XML文件中。如果有人可以就此提出任何建议，我将不胜感激。

一如既往地谢谢，

Answer 1

有几个人认为我可以做得更好，首先正如Andreas所说，你在每个循环中重新分配var $ new，所以请记住一个concat运算符点：

$new .= str_replace($find,$replace,$contents);

并且在循环结束时，您将在$ new上连接所有循环迭代。

我建议您打开文档：

<?php

而不是：

<?

通过这种方式，php将能够使用XML。

我建议使用特定的库来处理XML而不是你正在做的事情。

simpleXml PHP

更好的想法是构建你的xml并解析/保存使用磁盘工作的内容...将来你会遇到很多麻烦，特殊的字符，字符集......等等。

Answer 2

试试这个（未经测试）：

<?php

$filename = 'MYDRIVE\XML_TEMPLATE2.xml';
$contents = file_get_contents($filename); 

$emaillist = array(array('fname'            => 'Brad',
                         'lname'            => 'BoBo',
                         'recipient'        => 'bbobo@gmail.com'),  

                   array('fname'            => 'Josh',
                         'lname'            => 'Jojo',
                         'recipient'        => 'jjojo@gmail.com'),

                   array('fname'            => 'Sam',
                         'lname'            => 'Soso',
                         'recipient'        => 'ssoso@gmail.com'),

                   array('fname'            => 'Dave',
                         'lname'            => 'Dojo',
                         'recipient'        => 'ddojo@hotmail.com'));

// This will open/ create the file if non-existent.

$handle      = fopen("MYDRIVE/tempname.xml", "w+");
$filename    = 'MYDRIVE/tempname.xml';
$filecontent = '';
foreach ($emaillist as &$person) 
{

    $fname      = $person['fname'];
    $lname      = $person['lname'];
    $recipient  = $person['recipient'];
    $todaysdate = date("F j, Y, g:i a"); 

    $find       = array("[[firstname]]",
                        "[[lastname]]",
                        "[[recipient]]",
                        "[[todaysdate]]");

    $replace    = array($fname,
                        $lname,
                        $recipient,
                        $todaysdate);

    $new        = str_replace($find,
                              $replace,
                              $contents);

    $filecontent .= $new;
}
if (is_writable($filename)) 
{ 
    print "<b>Data added to file:</b>";
    print "<br>";
    print "<br>";

    if (!$handle = fopen($filename, 'a')) 
    {
         print "Cannot open file ($filename)";
         exit;
    }

    // Adds $filecontent to file.

    if (fwrite($handle, $filecontent) === FALSE) 
    {
        print "Cannot write to file ($filename)";
        exit;
    }

    print "Success! <br><br> ($filecontent) <br><br> was added to ($filename)";

    fclose($handle);

} 
else 
{
    print "<b>Error:</b>";
    print "The file $filename is not writable";
    exit();
}

// Generate file name for use.

$filenamegen = date("d_h_i_s");

if (rename ("MYDRIVE/tempname.xml", "MYDRIVE/" . $filenamegen . ".xml"))
{ 
    print "File successfully saved as : $filenamegen";
    print "<br><br>";
}
else
{
    print "Error renaming file.";
    exit();
}

print "</div>";

如果您的XML_TEMPLATE2.xml中有XML标题，则应将其删除，然后将其添加到$filecontent foreach - 循环之前。对于根节点也是如此 - 在foreach 之前将其打开并在foreach之后关闭它。

将PHP写入相同的XML文档，而不是为每次迭代创建一个

2 个答案: