我使用d3 js折叠树。
链接需要将矩形的末端连接到另一个矩形的起始位置。请点击这里查看图片 rect nodes d3 js
但我没有那样。 请帮我找到解决方案。
以下是我使用
的代码
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Tree Example</title>
<style>
.node {
cursor: pointer;
border-style: solid;
border-width: 2px 10px 4px 20px;
}
.node circle {
fill: #fff;
stroke: steelblue;
stroke-width: 3px;
}
.node rect {
fill: #fff;
stroke: steelblue;
stroke-width: 3px;
}
.node text {
font: 12px sans-serif;
}
.link {
fill: none;
stroke: #ccc;
stroke-width: 2px;
}
</style>
</head>
<body>
<!-- load the d3.js library -->
<script src="http://d3js.org/d3.v3.min.js"></script>
<script>
var treeData = [{
"name": "Top Level",
"parent": "null",
"children": [{
"name": "Level 2: A",
"parent": "Top Level",
"children": [{
"name": "Son of A",
"parent": "Level 2: A"
}, {
"name": "Daughter of A",
"parent": "Level 2: A"
}]
}, {
"name": "Level 2: B",
"parent": "Top Level"
}]
}];
// ************** Generate the tree diagram *****************
var margin = {
top: 20,
right: 120,
bottom: 20,
left: 120
},
width = 960 - margin.right - margin.left,
height = 500 - margin.top - margin.bottom;
var i = 0,
duration = 750,
root;
var tree = d3.layout.tree()
.size([height, width]);
var diagonal = d3.svg.diagonal()
.projection(function(d) {
return [d.y, d.x];
});
var svg = d3.select("body").append("svg")
.attr("width", width + margin.right + margin.left)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
root = treeData[0];
root.x0 = height / 2;
root.y0 = 0;
update(root);
d3.select(self.frameElement).style("height", "500px");
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
links = tree.links(nodes);
// Normalize for fixed-depth.
nodes.forEach(function(d) {
d.y = d.depth * 180;
});
// Update the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function(d) {
return d.id || (d.id = ++i);
});
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) {
return "translate(" + source.y0 + "," + source.x0 + ")";
})
.on("click", click);
nodeEnter.append("rect")
.attr("x", function(d) {
return d.children || d._children ? 0 : 0;
})
.attr("y", function(d) {
return d.children || d._children ? 15 : 15;
})
.attr("rx", 10)
.attr("ry", 10)
.attr("width", 10)
.attr("height", 10)
.style("fill", function(d) {
return d._children ? "lightsteelblue" : "#fff";
});
nodeEnter.append("text")
.attr("x", function(d) {
return d.children || d._children ? 60 : 13;
})
.attr("dy", ".35em")
.attr("text-anchor", function(d) {
return d.children || d._children ? "end" : "start";
})
.text(function(d) {
return d.name;
})
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) {
return "translate(" + d.y + "," + d.x + ")";
});
nodeUpdate.select("rect")
.attr("x", function(d) {
return d.children || d._children ? 0 : 0;
})
.attr("y", function(d) {
return d.children || d._children ? -15 : -15;
})
.attr("rx", 10)
.attr("ry", 10)
.attr("width", 150)
.attr("height", 30)
.style("fill", function(d) {
return d._children ? "lightsteelblue" : "#fff";
});
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) {
return "translate(" + source.y + "," + source.x + ")";
})
.remove();
nodeExit.select("rect")
.attr("x", function(d) {
return d.children || d._children ? 0 : 0;
})
.attr("y", function(d) {
return d.children || d._children ? 15 : 15;
})
.attr("rx", 10)
.attr("ry", 10)
.attr("width", 10)
.attr("height", 10);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = svg.selectAll("path.link")
.data(links, function(d) {
return d.target.id;
});
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {
x: source.x0,
y: source.y0
};
return diagonal({
source: o,
target: o
});
});
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {
x: source.x,
y: source.y
};
return diagonal({
source: o,
target: o
});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
}
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}
</script>
</body>
</html>
&#13;
答案 0 :(得分:0)
由于所有矩形的宽度都是150px,我们可以在对角线函数中对该值进行硬编码:
var diagonal = d3.svg.diagonal()
.source(function (d) {
return {"x": d.source.x, "y": d.source.y + 150};
})
.projection(function (d) { return [d.y + 0, d.x + 0];
});