Question

我有一个文本文件，包括一些数值，括号和逗号，如下所示：

[123,5],[345,21],[1567,34],[7689,234],....

所有数据都在一行中。我需要从这个文本文件中提取这些数字，并且需要定义两个变量，如X和Y，这样括号中的所有第一个元素都保存在变量X中，所有第二个元素都保存在变量中是的。我还想在excel文件中包含这两个变量X和Y。

Answer 1

假设您有一个名为# INITIALIZE LIST WITH DATE SEQUENCE DF newldf <- list(data.frame(Date = as.factor(seq(as.POSIXct("2016-10-01", tz = "UTC"), as.POSIXct("2016-10-31", tz = "UTC"), by = 'day')))) # APPEND LIST OF DATA FRAMES THAT ARE READ IN, EACH WITH SECOND COL = 1 newldf <- append(newldf, list(data.frame(Date = c("2016-10-01", "2016-10-02", "2016-10-03", "2016-10-04"), A = 1), data.frame(Date = c("2016-10-07", "2016-10-08", "2016-10-09"), B = 1), data.frame(Date = c("2016-10-15", "2016-10-16", "2016-10-17", "2016-10-18", "2016-10-19"), C=1))) # MERGE ALL DATA FAMES TOGETHER newDF <- Reduce(function(...) merge(..., by=c("Date"), all=T), newldf) newDF[is.na(newDF)] <- 0 # CONVERT NAs TO ZEROs newDF$Date <- as.POSIXct(newDF$Date, tz = "UTC") # CONVERT DATE TO POSIXct str(newDF) # 'data.frame': 31 obs. of 4 variables: # $ Date: POSIXct, format: "2016-10-01" "2016-10-02" ... # $ A : num 1 1 1 0 0 0 0 0 0 0 ... # $ B : num 0 0 0 0 0 0 1 1 1 0 ... # $ C : num 0 0 0 0 0 0 0 0 0 0 ... str(DF) # 'data.frame': 31 obs. of 4 variables: # $ Date: POSIXct, format: "2016-10-01" "2016-10-02" ... # $ A : num 1 1 1 0 0 0 0 0 0 0 ... # $ B : num 0 0 0 0 0 0 1 1 1 0 ... # $ C : num 0 0 0 0 0 0 0 0 0 0 ... all.equal(DF, newDF) # [1] TRUE的文件，您可以执行以下操作：

file.txt

使用Python从文本文件中提取数值

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