Java Fibonacci序列

Question

编写一个程序来计算前10个Fibonacci数，并将结果存储在一维数组中。在第二个数组中计算并存储系列中相邻数字的平均值。第一个数组应包含整数值和第二个浮点值。以整齐的格式输出两个数组的内容

 public static void main(String[] args) {
     //number of elements to generate in a series
     int limit = 10;

     long[] series = new long[limit];

     //create first 2 series elements
     series[0] = 1;
     series[1] = 1;

     //create the Fibonacci series and store it in an array
     for(int i=2; i < limit; i++){
         series[i] = series[i-1] + series[i-2];
     }

     //print the Fibonacci series numbers
     System.out.println("Fibonacci Series upto " + limit);
     for (int i = 0; i < limit; i++) {
         System.out.print(series[i] + " ");
     }
}

好的，所以第一部分工作正常，但现在创建一个数组来计算平均值对我来说有点棘手。到目前为止我试过了。

int[] numbers = new int[]{1,1,2,3,5,8,13,21,34,55};
int sum=0;
for (int i = 0; i < numbers.length ; i++) {        
     sum = (int) (sum + numbers[i]);
     double average = (double)sum/numbers.length;
     System.out.println("Average value of array elements is : " + average);
}

但它不能很好地工作。有人能给我一些启示吗？

Answer 1

您不应计算for loop内的平均值。将average移到循环外部，以便在sum准确时计算。

            int[] numbers = new int[]{1,1,2,3,5,8,13,21,34,55};
            int sum=0;
            for(int i=0; i < numbers.length ; i++){        
                 sum = (int) (sum + numbers[i]);
            }
            double average = (double)sum/numbers.length;
            System.out.println("Average value of array elements is : " + average);

Answer 2

试试这个：

int[] numbers = new int[]{1,1,2,3,5,8,13,21,34,55};
int sum=0;
for (int i = 0; i < numbers.length - 1; i++) {        
     sum = (int) (sum + numbers[i]);
     double average = sum/2.0;
     System.out.println("Average value of array elements is : " + average);
}