Question

我想向我的数据库中的所有用户发送推送通知，但是使用此代码我只向我的数据库中的最后一个用户发送通知。

<?php
$connect = mysqli_connect("localhost", "***", "***", "***");

$message = $_POST["message"];
$title = $_POST["title"];
$path = "https://fcm.googleapis.com/fcm/send";
$server_key = "***";
$sql = "SELECT fcm_token FROM User";
$result = mysqli_query($connect, $sql);

while($row = mysqli_fetch_assoc($result)) {
    $headers = array("Authorization:key=" .$server_key, "Content-Type:application/json");
    $fields = array("to"=>$row["fcm_token"], "notification"=>array("title"=>$title, "body"=>$message));
    $payload = json_encode($fields);
    $curl_session = curl_init();
    curl_setopt($curl_session, CURLOPT_URL, $path);
    curl_setopt($curl_session, CURLOPT_POST, true);
    curl_setopt($curl_session, CURLOPT_HTTPHEADER, $headers);
    curl_setopt($curl_session, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl_session, CURLOPT_SSL_VERIFYPEER, false);
    curl_setopt($curl_session, CURLOPT_IPRESOLVE, CURL_IFRESOLVE_V4);
    curl_setopt($curl_session, CURLOPT_POSTFIELDS, $payload);
}

$result = curl_exec($curl_session);

curl_close($curl_session);
mysqli_close($connect);


$response = array();
$response["success"] = true;

echo json_encode($response);
?>

有人知道解决方案吗？

Answer 1

您需要在while循环中执行您的请求。因此，您需要以下列方式重写代码：

<?php
$connect = mysqli_connect("localhost", "***", "***", "***");

$message = $_POST["message"];
$title = $_POST["title"];
$path = "https://fcm.googleapis.com/fcm/send";
$server_key = "***";
$sql = "SELECT fcm_token FROM User";
$result = mysqli_query($connect, $sql);

while($row = mysqli_fetch_assoc($result)) {
    $headers = array("Authorization:key=" .$server_key, "Content-Type:application/json");
    $fields = array("to"=>$row["fcm_token"], "notification"=>array("title"=>$title, "body"=>$message));
    $payload = json_encode($fields);
    $curl_session = curl_init();
    curl_setopt($curl_session, CURLOPT_URL, $path);
    curl_setopt($curl_session, CURLOPT_POST, true);
    curl_setopt($curl_session, CURLOPT_HTTPHEADER, $headers);
    curl_setopt($curl_session, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl_session, CURLOPT_SSL_VERIFYPEER, false);
    curl_setopt($curl_session, CURLOPT_IPRESOLVE, CURL_IFRESOLVE_V4);
    curl_setopt($curl_session, CURLOPT_POSTFIELDS, $payload);

    $curl_result = curl_exec($curl_session);
    curl_close($curl_session);
}

mysqli_close($connect);

$response = array();
$response["success"] = true;

echo json_encode($response);
?>

Answer 2

最好收集所有FCM令牌并使用registration_ids确保只向FCM服务器发送一个HTTP请求。您可以找到完整的FCM HTTP协议here。

<?php

$connect = mysqli_connect("localhost", "***", "***", "***");

$message = $_POST["message"];
$title = $_POST["title"];
$path = "https://fcm.googleapis.com/fcm/send";
$server_key = "***";
$sql = "SELECT fcm_token FROM User";
$result = mysqli_query($connect, $sql);

$tokens = array();
while($row = mysqli_fetch_assoc($result)) {
    $tokens[] = $row["fcm_token"];
}

$headers = array("Authorization:key=" . $server_key, "Content-Type:application/json");
$fields = array(
    "registration_ids" => $tokens,
    "notification" => array("title" => $title, "body" => $message)
);
$payload = json_encode($fields);

$curl_session = curl_init();
curl_setopt($curl_session, CURLOPT_URL, $path);
curl_setopt($curl_session, CURLOPT_POST, true);
curl_setopt($curl_session, CURLOPT_HTTPHEADER, $headers);
curl_setopt($curl_session, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl_session, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($curl_session, CURLOPT_IPRESOLVE, CURL_IFRESOLVE_V4);
curl_setopt($curl_session, CURLOPT_POSTFIELDS, $payload);

$curl_result = curl_exec($curl_session);
curl_close($curl_session);

mysqli_close($connect);

$response = array();
$response["success"] = true;

echo json_encode($response);

?>

Android，向多个用户发送推送通知

2 个答案: