Question

我想问一个关于shell脚本的问题假设有两个路径可以安装文件 Path_1或Path_2

首先应该在Path_1上查找该文件如果文件不存在或安装在Path_1上那么脚本应该在path_2上查找文件如果它不存在那么显示错误

我有这个代码： -

# Make sure that sh.exe is found in C:\Program Files (x86)\Git\bin\sh.exe
ls /c/Program\ Files\ \(x86\)/Git/bin/sh.exe > /dev/null 2>&1 || {
    echo
    echo -e "\t Git Bash was not installed in the default location."
    echo -e '\t Installation requires sh.exe to be found at C:\Program Files (x86)\Git\\bin\sh.exe.'
    echo
    echo -e "\e[0;31mAborting...\e[m"
    waitForEnterAndExit
}
echo -e "\t Git Bash installation found in C:\Program Files (x86)/Git/bin/sh.exe"

现在可以在

安装sh.exe

C：\ Program Files \ Git \ bin

或

 C:\Program Files (x86)\Git\bin\sh.exe

现在我想更改脚本，以便首先在

检查文件

C：\ Program Files \ Git \ bin

如果文件不在那里，那么

 C:\Program Files (x86)\Git\bin\sh.exe

Answer 1

以下是您可以部署的简单示例代码，并确保修改Path_1＆amp;的值。 PATH_2。

#!/bin/bash                                                                                                                                                                                                  

Path_1="path1"
Path_2="path2"

Filename=$1

[ -z ${Filename} ] && echo Filename cannot be empty && exit -1

[ -e ${Path_1}/${Filename} ] && echo Found ${Filename} under ${Path_1} && exit 0
[ -e ${Path_2}/${Filename} ] && echo Found ${Filename} under ${Path_2} && exit 0

echo ${Filename} cannot be found under ${Path_1} and ${Path_2} && exit -1

shell脚本 - 文件存在

1 个答案: