LUA读取文本文件，进行拆分并发送到数组

Question

我是lua的新手。实际上这个脚本用于游戏服务器，但我需要帮助从我的商店.txt文件中获取值。所以我的商店系统是每个玩家将保存在一个文件中。

存储文件

我的文本文件

中的语法数据

[name]:[points]:[which var point earned on index]

我的示例数据（此var点实际上是来自lua文件的写入数据，发送到文本文件）

jack:60:4
ronald:40:1
jack:30:1

所以当我从上面得到的是

列表

local player = {{(name),(points),(which var point earned on index)},
                {(name),(points),(which var point earned on index)},...};

我自己的代码

local line_data = {}
local point_file = io.open("points.txt", "r")
for line in point_file:lines() do
  local playername, playerpoint, playervarpointname = line:match("(%d+):(%d+):(%d+)")
  local player_data = {playername, playerpoint, playervarpointname}
  for i = 1, #line do
        player_data = [#player_data + 1] = line[i];
  end
  line_data[#line_data + 1] = player_data
end

这是正确的代码吗？

Answer 1

local line_data = {}
local point_file = io.open("points.txt", "r")
for line in point_file:lines() do
  local playername, playerpoint, playervarpointname = line:match("([^:]+):(%d+):(%d+)")
  local player_data = {playername, playerpoint, playervarpointname}
 table.insert(line_data, player_data)
end

或者，imho，'[a-zA-Z0-9] +'，可以代替'[^：] +'