Question

我正在使用XmlHTTPRequest对象异步调用PHP脚本，但我在输出中得到var_dump的返回值。

这是响应文本（我已经编辑了我的电子邮件）：

array(5) {
["UID"]=>
string(1) "3"
["NAME"]=>
string(15) "Henry Kissenger"
["EMAIL"]=>
string(25) "******@*******.com"
["PASS"]=>
string(34) "$1$.nDZEZgZ$QKuE.mhlBPDZ3WdhwkiPC1"
["TITLE"]=>
string(9) "Exchequer"
}
3 | Exchequer | Henry Kissenger | ******@*******.com |

在PHP脚本和类中没有任何地方被调用，甚至进行了查找/替换以确保它不被调用。相关代码如下，在其中很多都找不到var_dump。

getSingleUser.php，由xhr obj调用

<?php
session_start();

$pathUser = __DIR__."/../user/uClass_v2.php";
require $pathUser;

$user = User::withID($_SESSION["UID"]);

echo "$user->ID | $user->title | $user->name | $user->email | ";
?>

uClass_v2.php，相关功能。

//queries db for user with ID, then returns the instance.
public static function withID($ID)
{
    $instance = new self();
    $instance->loadByID($ID);
    return $instance;
}

//queries the user table using the queryByUID() funct, then fill()s
public function loadByID($ID)
{
    $result = $this->queryByUID($ID);
    $this->fill($result);
}


//queries user table, returns the assoc array.
public function queryByUID($ID)
{
    $this->CON = new mysqli("domain.name","kevin","******","tbd");

    $query = "SELECT * FROM User WHERE UID =".$ID;
    $results = $this->CON->query($query);

    if($results->num_rows > 0)
    {
        return $results->fetch_assoc();
    }

}

#accepts array, performs checks to ensure not empty or not meeting assoc array format required, then sets object properties. 
public function fill(array $row)
{
    //counts number of array elements, to decide if existing user or creating new user.
    $noElements = count($row);

    if($noElements <= 0 || $noElements > 5)
    {
        //return "incorrect # elements";
    }else if($noElements == 4)
    {
        //registering new user, leave UID unset.
        //not sure if isset checks are required. 
        if(isset($row["name"])   && 
             isset($row["title"])&& 
             isset($row["email"])&& 
             isset($row["pass"]))
        {
            $this->name = $row["name"];
            $this->title = $row["title"];
            $this->email = $row["email"];
            // @ below = shut up about salts php7
            $this->pass = @crypt($row["pass"]);
        }
        else
        {
            //return "not all element set.";
        }   
    }else if($noElements == 5)
    {   //existing user, from db row.
        $this->name  = $row["NAME"];
        $this->title = $row["TITLE"];
        $this->email = $row["EMAIL"];
        $this->ID   = $row["UID"];
        $this->pass  = $row["PASS"];
    }else
    {
        //echo "I don't think you should ever see this";
    }
}

这只是在我的廉价托管服务转移到我自己的服务器之后才发生的。这是我的Apache / php.ini中的错误配置吗？

如果这看起来很熟悉，请告诉我，我对此感到非常沮丧！

Answer 1

它不再这样做，这是我所做的改变。

在start_session上禁止警告，没有修复 @session_start();
评论出每一个回声，然后取消评论它们似乎解决了这个问题，但我不能为我的生活找到原因。 //echo "someString"; - ＆GT; echo "someString";
几次重新启动httpd，没有更改httpd.conf或php.ini

如果有人能够解释这一点，我会永远感激。

xhr响应中

1 个答案: