Question

这基本上是我的第一个小C＃程序。我建立了一个＆＃34;规则＆＃34;所以你只有20次尝试猜测正确的数字。我想知道是否有更美妙的方式来实现这个＆＃34;规则＆＃34;。

这是我的代码：

        bool run = true;


        while (run == true) // Main While Schleife
        {

            Random rndnr = new Random();
            int rnd;
            rnd = rndnr.Next(1, 100);
            int guess;
            int trys;
            trys = 0;
            guess = 0;



            Console.WriteLine("Can you guess my number? I am thinking about a number between 1 and 100!");
            guess = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine(rnd);

            while (guess != rnd)
            {


                if (trys > 20)
                {
                    Console.Clear();
                    Console.WriteLine("You only have 20 trys. You failed! \n");
                    run = false;
                    Console.WriteLine("Do you wann play again? Press R + Enter to play again!");
                    string rerun = Console.ReadLine().ToUpper();
                    if (rerun == "R")
                    {
                        run = true;
                        trys = 0;
                        Console.Clear();
                        break;
                    }
                    else
                    {
                        run = false;
                        break;

                    }


                }





            if (guess > rnd)
            {
                Console.WriteLine("My number is lower than" + guess + "\n guess again >>");
                guess = Convert.ToInt32(Console.ReadLine());

            }

            if (guess < rnd)
            {
                Console.WriteLine("My number is higher than" + guess + "\n guess again >>");
                guess = Convert.ToInt32(Console.ReadLine());

            }

            if (guess == rnd)
            {

                Console.Write("You guessed right my number is" + rnd + "and you needed " + trys + "trys");
                run = false;
                Console.WriteLine("Do you wann play again? Press R + Enter to play again!");
                string rerun = Console.ReadLine().ToUpper();

                if (rerun == "R")
                {
                    run = true;
                    trys = 0;
                    Console.Clear();
                }

                else
                {
                    run = false;
                    break;
                }
            }


            trys++;
            }




        }
        Console.Clear();
        Console.WriteLine("Thanks for palying see you next time!");
        Console.ReadLine();
    }
}

Answer 1

我做了一些错误修复，并且通常尝试改进代码。希望你觉得它有用：

    bool run = true;
    int maxTrys=20;
    Random random = new Random();

    while (run)
    {
        int rnd=random.Next(1, 101);

        Console.WriteLine("Can you guess my number? I am thinking about a number between 1 and 100!");
        int trys=0;
        bool solved=false;
        while (!solved && trys<maxTrys)
        {
            trys++;
            int guess;
            bool numericGuess;
            do {
                numericGuess=int.TryParse(Console.ReadLine(), out guess);
                if (!numericGuess) {
                    Console.WriteLine("Please enter a number");
                }
            } while (!numericGuess);

            if (guess > rnd)
            {
                Console.WriteLine(string.Format("My number is lower than {0}\n guess again >>", guess));
            }
            else if (guess < rnd)
            {
                Console.WriteLine(string.Format("My number is higher than {0}\n guess again >>", guess));
            }
            else if (guess == rnd)
            {
                solved=true;
                Console.WriteLine(string.Format("You guessed right my number is {0} and you needed {1} trys", rnd, trys));
            }
        }
        if (!solved) {
            Console.Clear();
            Console.WriteLine(string.Format("You only have {0} trys. You failed! \n", maxTrys));
        }

        Console.WriteLine("Do you wanna play again? Press R + Enter to play again!");
        string rerun = Console.ReadLine().ToUpper();

        if (!rerun.Equals("R"))
        {
            run = false;
        }
    }
    Console.Clear();
    Console.WriteLine("Thanks for playing see you next time!");
    Console.ReadLine();

Answer 2

 Random r = new Random();

            int secretNumber = r.Next(1, 11);
            int i = 0;
            int chance = 5;

            Console.WriteLine("Game: guess number");

            while (i < chance)
            {
                Console.WriteLine("Your turn");

                if (secretNumber == int.Parse(Console.ReadLine()))
                {
                    Console.WriteLine("You won!");
                    break;
                }

                i++;
            }

            if (i == chance)
            {
                Console.WriteLine("You lost!");
                Console.WriteLine("The secret number is " + secretNumber);
            }

简单方法

C＃猜测只有X次尝试的游戏

2 个答案: