Question

有一个像id-name-roll这样的表我有一些常量给定值的卷像 - （1,2,6,8,5）让它成为A. 表有滚动像（1,2,3,4,5,6,7）让它设置为B. 我想知道A-B 表示滚动值不在表中但存在于给定常量集A

中的值我试过了从＆＃34; tablename＆＃34;中选择滚动哪里不滚（1,2,6,8,5）; 但它恰好相反 - 它返回B-A 但我想要A-B 请帮忙我也试过了

从tablename中选择（1,2,6,8,5）来自双减去选择滚动; 但它给出了一些syntex错误

Answer 1

这是你想要的吗？

select a.*
from (select 1 as id from dual union all
      select 2 as id from dual union all
      select 6 as id from dual union all
      select 8 as id from dual union all
      select 5 as id from dual
     ) a
where not exists (select 1 from b where a.id = b.id);

Answer 2

(select 1 as id from dual
         union all
select 2 from dual
         union all
select 6 from dual
         union all
select 8 from dual
         union all
select 5 from dual
         )
minus
Select id from b

减去oracle中一列值的一组常量值

2 个答案: