在AWS Lambda中集成Google Guice

时间:2016-10-29 17:32:27

标签: java java-8 guice aws-lambda guice-3

我尝试将Google Guice集成到AWS Lambda中,但由于某些原因,注入效果不佳。每当我尝试拨打

时,它都会给我null

处理程序代码:

public class FirstLamdba implements RequestHandler<Request, Object>{   

        private UserService userService;

        @Inject
        public void seUserService(UserService userService) {
            this.userService = userService;
        }

        public Object handleRequest(Request request, Context context){

            userService.persistData();
}

UserService

public interface UserService {
    List<String> persistData();
}

UserServiceImpl

public class UserServiceImpl implements UserService{


    @Override
    public List<String> persistData() {

        System.out.println("***Working*********");
}

绑定类:

public class MessageGuiceModule extends AbstractModule
{
  protected void configure() {

    bind(UserService.class).to(UserServiceImpl.class);
  }
}

测试类:

 @Test
        public void testLambdaFunctionHandler() {
Request request = new Request();
            request.setName("Name");
            FirstLamdba handler = new FirstLamdba();
            Context ctx = createContext();

            Object output = handler.handleRequest(request, ctx);

            // TODO: validate output here if needed.
            if (output != null) {
                System.out.println(output.toString());
            }
        }

由于某些原因,UserService userService在FirstLamdba中设置为null。

有什么想法吗?

2 个答案:

答案 0 :(得分:3)

第一次调用lambda函数时,将创建环境。

public class FirstLamdba implements RequestHandler<Request, Object>{   

        Injector injector = Guice.createInjector(new MessageGuiceModule());
        private UserService userService = injector.getInstance(UserService.class);


        //setter for testing purpose
        public void setUserService(UserService userService) {
            this.userService = userService;
        }

        public Object handleRequest(Request request, Context context){

            userService.persistData();
}


@Test
public void testLambdaFunctionHandler() {
        Request request = new Request();
        request.setName("Name");
        FirstLamdba handler = new FirstLamdba();
        handler.setUserService(mockUserService);

        Context ctx = createContext();

        Object output = handler.handleRequest(request, ctx);

        // TODO: validate output here if needed.
        if (output != null) {
            System.out.println(output.toString());
        }
}

答案 1 :(得分:1)

Lambda RequestHandler实例没有使用Guice,因此在@Inject类中直接使用RequestHandler不起作用。这就是您userService属性始终为null的原因。

我没有尝试过将Guice与Lambda一起使用,但我相信你必须在某些时候显式调用Guice.createInjector()才能引导Guice依赖注入。

一般情况下,在开发AWS Lambda函数时,我建议从一个POJO开始,它执行引导库的操作,并公开一个像persistUser()这样的高级方法,您可以轻松地运行并独立于任何Lambda特定的测试码。一旦你开始工作,你的Lambda函数就会只是几行代码来实例化这个POJO的一个实例并调用persistUser()方法。