这让我发疯,我确信这很简单。我得到的值必须包含至少一个元素'当我尝试从出现的表中输入预订时,服务器出错。一切正常。无论我在VALUES部分使用引号还是在分隔逗号上加上(+)符号或引号,我都会收到不同的错误消息。当我在table_num上添加引号时,我得到并且错误告诉我您无法将CHAR插入INTEGER。当我删除引号时,我得到错误告诉我 - 严重:java.sql.SQLSyntaxErrorException:Column' TABLE_NUM'要么不在FROM列表中的任何表中,要么出现在连接规范等中。有人能告诉我发生了什么吗?这是jsp代码。提前谢谢。
<%
int tableNum = 0;
String firstName = null;
String lastName = null;
String Address = null;
int Phone = 0;
java.sql.Date date = null;
int People = 0;
if (request.getParameter("table_num")!=null){
tableNum = Integer.parseInt(request.getParameter("table_num"));
}
if (request.getParameter("first")!=null){
firstName = request.getParameter("first");
}
if (request.getParameter("last")!=null){
lastName = request.getParameter("last");
}
if (request.getParameter("address")!=null){
Address = request.getParameter("address");
}
if (request.getParameter("phone")!=null){
Phone = Integer.parseInt(request.getParameter("phone"));
}
if (request.getParameter("date")!=null){
java.util.Date utilDate = new java.util.Date(request.getParameter("date"));
date = new java.sql.Date(utilDate.getTime());
}
if (request.getParameter("people")!=null){
People = Integer.parseInt(request.getParameter("people"));
}
if(tableNum != 0 && firstName != null && lastName != null && Address != null && Phone != 0 && date != null && People != 0){
String URL = "jdbc:derby://localhost:1527/Reservations";
String USERNAME= "johnpaul";
String PASSWORD= "purlease";
Connection myCon = null;
Statement ste = null;
PreparedStatement preparedStmt = null;
try{
Class.forName("org.apache.derby.jdbc.ClientDriver");
System.out.println("Connecting to DB...");
Connection con=DriverManager.getConnection("jdbc:derby://localhost:1527/Reservations","johnpaul", "purlease");
System.out.println("Connected successfuly");
System.out.println("Inserting records into table");
Statement st = con.createStatement();
String query = "INSERT INTO JOHNPAUL.CUSTOMER_RESERVATIONS(TABLE_NUM,FIRST_NAME,LAST_NAME,ADDRESS,TELEPHONE,DATE,NUMBER_IN_PARTY)VALUES(table_num,first,last,address,phone,date,people)";
st.executeUpdate (query);
System.out.println("Records inserted");
}catch(SQLException se){
se.printStackTrace();
}catch(ClassNotFoundException se){
//Handle errors for JDBC
se.printStackTrace();
}catch(Exception e){
//Handle errors for Class.forName
e.printStackTrace();
}
}
%>
答案 0 :(得分:0)
您的问题似乎在这里:
String query = "INSERT INTO JOHNPAUL.CUSTOMER_RESERVATIONS
(TABLE_NUM, FIRST_NAME,LAST_NAME,ADDRESS,TELEPHONE, DATE, NUMBER_IN_PARTY)
VALUES (table_num, first,last,address,phone,date,people)";
这里有两件事: 逃避你的弦乐;和 2.将变量中的值连接到字符串。
String query = "INSERT INTO JOHNPAUL.CUSTOMER_RESERVATIONS
(TABLE_NUM, FIRST_NAME,LAST_NAME,ADDRESS,TELEPHONE, DATE, NUMBER_IN_PARTY)
VALUES (" + table_num + ", '" + first + "', '" + last + "', '" + address + "', " + phone + " , '" + date + "', " + people + ");";
您可能必须验证数据库引擎期望日期字段的格式。