Question

所以我有一个问题：

我的程序必须找到数组中最常见的元素。我们必须使用calloc创建此数组。我的代码正在运行，但我被要求将部分代码移动到一个函数中，我必须创建一个数组并输入数字。

int main() {
    int n, i, dazn;
    int *A;
    dazn = 0;
    printf("Iveskite naturalu skaiciu: \n");// enter how many elements in an array we will have
    scanf("%d", &n);
    A = (int*)calloc(n, sizeof(int)); // Starting from here...
    for (i = 0; i < n; i++) {
        printf("Iveskite skaiciu \n"); 
        scanf("%d", &A[i]); // 
    }
    ... // and ending here have to be in a function
    ... // sorting and finding the most common element

Answer 1

按照说明，将代码移动到单独的函数：

#include <stdio.h>
#include <stdlib.h>

int *allocate_and_read_array(int size) {
    int *A = (int*)calloc(size, sizeof(int));
    if (A != NULL) {
        for (int i = 0; i < size; i++) {
            printf("Iveskite skaiciu \n"); 
            if (scanf("%d", &A[i]) != 1) {
                printf("Missing values\n");
                break;
            }
        }
    }
    return A;
}

int main(void) {
    int n, i, dazn;
    int *A;
    dazn = 0;
    printf("Iveskite naturalu skaiciu: \n");// enter how many elements in an array we will have
    scanf("%d", &n);
    A = allocate_and_read_array(n);

    ... // sort the array
    ... // find the most common element

    free(A);
    return 0;
}

将calloc返回数组返回main

1 个答案: