Question

我正在尝试在我的项目上实现一个简单的登录功能，但由于某种原因它没有按预期工作（或根本没有）。我无法从php表单中获取operator+属性的数据，因此我可以继续登录。由于某种原因，根本没有获取数据。我是网络开发的新手，所以请帮助。

这是包含表格

的模态

name

这是用于登录的php：

 <div class="modal-content">
    <div class="modal-header">
      <button type="button" class="close" data-dismiss="modal">&times;</button>
      <h4 class="modal-title">LOGIN</h4>
    </div>
    <div class="modal-body">
      <p>Please, enter your login details.</p>
    </div>


    <form method="POST" action="homePage.php">
      <div class="row">
        <div class="col-xs-7">
          <input type="text" name="txtUserEmail" class="form-control modalForm" id="usr" placeholder=" CPR 000000-0000">
        </div>
      </div>
      <div class="row">
        <div class="col-xs-7">
         <input type="password" class="form-control modalForm" name="txtUserPassword" id="pwd" placeholder="Password">
        </div>
      </div>
      <button type="button" class="btn btn-info modalForm" data-dismiss="modal">Login</button>
    </form>


    <div class="modal-footer">

    </div>
  </div>

任何意见都将受到赞赏。

Answer 1

在按钮标签

中设置名称=“提交”并输入=“提交”

<button name="submit" type="submit" class="btn btn-info modalForm" data-dismiss="modal">Login</button>

并设置这样的条件

 if(isset($_POST['submit'])){
 $arr = array();
 foreach ($json_a as $json_r) {
   if ($json_r['userName']==$_POST["txtUserEmail"] && $json_r['pass']==$_POST["txtUserPassword"] ) {
   file_put_contents("prods.json",$json_r['userName']);

  if ($json_r['isAdmin']==1) {
    $_SESSION['userEmail'] = $json_r['userName'];
    header('location: adminPage.php');
    # code...
  }else{
    $_SESSION['userEmail'] = $json_r['userName'];
    header('location: patientPage.php');
     }
  }
 }
}

Answer 2

试试这个

<div class="modal-content">
<div class="modal-header">
  <button type="button" class="close" data-dismiss="modal">&times;</button>
  <h4 class="modal-title">LOGIN</h4>
</div>
<div class="modal-body">
  <p>Please, enter your login details.</p>
</div>


<form method="POST" action="homePage.php">
  <div class="row">
    <div class="col-xs-7">
      <input type="text" name="txtUserEmail" class="form-control modalForm" id="usr" placeholder=" CPR 000000-0000">
    </div>
  </div>
  <div class="row">
    <div class="col-xs-7">
     <input type="password" class="form-control modalForm" name="txtUserPassword" id="pwd" placeholder="Password">
    </div>
  </div>
  <button type="submit" class="btn btn-info modalForm" >Login</button>
</form>


<div class="modal-footer">

</div>

使用Bootstrap和php无效的模态登录表单

2 个答案: