Question

初学者在这里。如前所述，我的问题是：当输入是字符串而不是int时，如何输出错误？我试图创建一个输出工人加薪的程序，我想实现一个函数，当用户输入工资以外的其他数字时会显示错误。这是我的代码：

package calculating.salary;
import java.util.Scanner;

public class CalculatingSalary {



public static void main(String[] args) {

    Scanner in = new Scanner(System.in);

    System.out.println("Please input yearly salary:");

    int salary = in.nextInt();
    //this is where I would implement the error message

    System.out.println("Please input how many years worked:");

    boolean running = true;
    while (running){

    String years = in.nextLine();

    if (years.equals ("1")|| years.equals("one")){
        System.out.println("Your salary is now $"+(salary + salary*0.02));
        break;
    }

    if (years.equals("2")||years.equals("two")){
         System.out.println("Your salary is now $"+(salary + salary*0.03));
        break;
    }
    if (years.equals("3")||years.equals("three")){
         System.out.println("Your salary is now $"+(salary + salary*0.04));
        break;
    }
    if (years.equals("4")||years.equals("four")){
         System.out.println("Your salary is now $"+(salary + salary*0.05));
        break;
    }
    if (years.equals("5")||years.equals("five")){
         System.out.println("Your salary is now $"+(salary + salary*0.06));
        break;
    }       
        else {
        System.out.println("Please type in a number from 1 through 5");
    }
}
    }
 }

Answer 1

String salary = in.nextLine();
int salaryValue;
try {
    salaryValue = Integer.parseInt(salary);
} catch (NumberFormatException e) {
    System.out.println("You didn't enter a valid integer.");
}

这会将用户的输入存储在String而不是int中，然后单独管理转换。如果转换失败，则抛出异常，从而导致打印消息。

当输入是字符串而不是int时，如何生成错误消息

1 个答案: