访问.jar资源时出现IO异常

Question

我在tomcat 8中部署了一个war。在其中一个jar中有abc.xml文件。现在，如果我试图在sample_jar的一个java类（Example.java）中的abc.xml上打开输入流，我将得到以下异常

Caused by: java.io.IOException: Stream closed
               at java.util.zip.InflaterInputStream.ensureOpen(InflaterInputStream.java:67)
       ~[?:1.8.0_102]
               at java.util.zip.InflaterInputStream.read(InflaterInputStream.java:121)
       ~[?:1.8.0_102]
               at org.apache.catalina.webresources.AbstractArchiveResource$JarInputStreamWrapper.read(AbstractArchiveResource.java:243)
       ~[catalina.jar:?]
               at com.sun.org.apache.xerces.internal.impl.XMLEntityManager$RewindableInputStream.read(XMLEntityManager.java:2890)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(XMLEntityManager.java:674)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.impl.XMLVersionDetector.determineDocVersion(XMLVersionDetector.java:148)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:805)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:770)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:141)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1213)
       ~[?:1.8.0_102]
               at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(SAXParserImpl.java:643)
       ~[?:1.8.0_102]
               at org.apache.commons.digester.Digester.parse(Digester.java:1892)
       ~[commons-digester-2.1.jar:2.1]
               at net.sf.jasperreports.engine.xml.JRXmlLoader.loadXML(JRXmlLoader.java:298)
       ~[jasperreports-6.3.0.jar:6.3.0

现在奇怪的是它只是第一次发生（一旦战争部署和服务器启动），后续访问它运行正常。 我创建流的方式是 -
InputStream is= Example.class.getResourceAsStream("/abc.xml"); 如果有人能指出错误，我将非常感激。

编辑-1 我正在访问文件的代码块 -

public class ReportManager {
    public void pageSetting(Map<String, Object> map){
    //code to set report's global info
    }
    public void createReport(String time) {
        try(InputStream coverStream = ReportManager.class.getResourceAsStream("ReportCover");
InputStream reportStream = ReportManager.class.getResourceAsStream("ReportDetail")) {
            JasperReport jasperReport1 = JasperCompileManager.compileReport(coverStream);                   
            JasperReport jasperReport2 = JasperCompileManager.compileReport(reportStream);
            Map<String, Object> templateParameters = new HashMap<String, Object>();
            Map<String, Object> coverTemplateParameters = new HashMap<String, Object>();
            pageSetting(coverTemplateParameters);
            pageSetting(templateParameters);
            JasperPrint jasperPrint1 = JasperFillManager.fillReport(jasperReport1, coverTemplateParameters,
                    new JREmptyDataSource());
            JasperPrint jasperPrint2 = JasperFillManager.fillReport(jasperReport2, templateParameters,
                    new JREmptyDataSource());
            List<JasperPrint> list = new ArrayList<>();
            list.add(jasperPrint1);
            list.add(jasperPrint2);
            JRPdfExporter exporter = new JRPdfExporter();
            exporter.setExporterInput(SimpleExporterInput.getInstance(list));
            exporter.setExporterOutput(
                    new SimpleOutputStreamExporterOutput(System.getProperty("java.io.tmpdir") + File.separator + "Report_Output"+ time + ".pdf"));
            exporter.exportReport();
        } catch (JRException | GeneralException | IOException e2) {
            logger.error("exception in report generation", e2);
        }
        }
    }