Bash脚本仅在第一个匹配和第二个匹配之间输出文本

Question

尝试在开始之前和字符串结束之后匹配。这个问题似乎在我的小巷里：How to use sed/grep to extract text between two words?

我设法匹配开始（第一场比赛）。但是对于结束（第二场比赛），它与最后一场比赛相匹配。

示例字符串：

Bob said that John is nice, which makes Bob nice.

我想得到“John is”，所以我寻找“Bob said”之间的字符串

baz="Bob said that John is nice, which makes Bob nice."
echo `echo "$baz" | sed 's/Bob said that \(.*\) nice/\1/'`
#result: John is nice, which makes Bob.

它与 last “nice”匹配，而不是 next 。有没有办法匹配下一个“好”？