Question

我的ToDo应用程序数据库有以下cloumns：

| ID | ShortDescription | Description | Date | Status |

我已经可以在Datatable中添加一个Task，可以在 phphmyadmin 中看到它。

到目前为止，我有以下代码：

$id = mysql_real_escape_string($_GET['id']);

$out = 'SELECT * FROM ToDo1 WHERE `id` = '.$id.' LIMIT 1';
$result = mysqli_query($link, $out);

$row= mysqli_fetch_array($result);
?>

<div id= "OutShortDescription">
<?php
echo $row['ShortDescription'];
?>
</div>
<div id= "OutDescription">
<?php
echo $row['Description'];
?>
</div>
<div id= "OutDate">
<?php
echo $row['Date'];
?>
</div>
<div id= "OutStatus">
<?php
echo $row['Status'];
?>
</div>

现在我想将每个ID行放在自己的网站上。为此，我想制作一个按钮表（ Buttonnumber = ID ）。在此按钮上只应显示ShortDescription，当我点击它时，我想转到与按钮匹配的网站。

有人可以帮助我吗？

修改

好的，谢谢，我现在有了这段代码，但它无法正常工作：

    <?php
       $dbname= 'Groups';
       $dsn = 'mysql:host=localhost;dbname='.$dbname;
       $user = 'root';
       $pass = '';
       $db  = new PDO($dsn, $user,$pass);
       $query = "SELECT * FROM groups2 WHERE id = :id LIMIT 1";
       $ps = $db->prepare($query);
       $ps->bindParam(':id', $id);
       $ps->execute();
       $row = $ps->fetch(PDO::FETCH_ASSOC);


       ?>
  <div class="searchwindow">
  <?php
  $data = $link->query('SELECT * FROM Groups2');

foreach($data as $row) { 

 echo '<p><input type="button" onclick="window.location = All_Groups.php?id=' . $row['ID'] . ' value='.$row['ShortDescription'].'  /></p>';
    }

我现在有以下代码

<div data-role="page" id="SearchPage" data-title="SearchPage">
      <div data-role="header">
        <h1>Search</h1>
      </div>

      <div data-role="content">



    <div data-role="header">    

<form>
<fieldset data-role="controlgroup" data-type="horizontal" data-mini="true" align="center" id="selectMenu">


    <select name="selectStatus" id="selectStatus">
        <option value="0">Status</option>
        <option value="1">Done</option>
        <option value="2">In Progress</option>
    </select>


</fieldset>
</form>

</div>
       <?php
       $dbname= 'Groups';
       $dsn = 'mysql:host=localhost;dbname='.$dbname;
       $user = 'root';
       $pass = '';
       $db  = new PDO($dsn, $user,$pass);
       $query = "SELECT * FROM groups2 WHERE id = :id LIMIT 1";
       $ps = $db->prepare($query);
       $ps->bindParam(':id', $id);
       $ps->execute();
       $row = $ps->fetch(PDO::FETCH_ASSOC);


       ?>
  <div class="searchwindow">
  <?php
  $data = $link->query('SELECT * FROM Groups2');

foreach($data as $row) { 

 $path = $row['ID'];
 $description = $row['ShortDescription'];
 echo ("<form action='All_Groups.php?id=$path'><button  type='submit' value='$description'/>$description</form>" );
}
  ?>



  </div>    
</div>

<div data-role="footer" data-position="fixed">
    <div data-role="navbar">
      <ul>
        <li><a href="#SearchPage" data-transition="slideup" data-icon="search" data-iconpos="top">Search</a></li>
        <li><a href="#NewPage" data-transition="slideup" data-icon="plus" data-iconpos="top">New</a></li>
        <li><a href="#MorePage" data-transition="slideup" data-icon="bars" data-iconpos="top">More</a></li>
      </ul>
    </div><!-- Ende navbar -->
  </div><!-- Ende footer -->
  </div>

这是我的All_groups.php

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Unbenanntes Dokument</title>
</head>

<body>
<?php
$servername ="localhost";
    $username = "root";
    $password = "";
    $dbname = "Groups";

    $link = mysqli_connect($servername, $username, $password, $dbname);
if (!$link) {
    die('Verbindung nicht möglich : ' . mysqli_error($link) );
}
    ?>

<?php

$row="";
$Date="";
$Status="";
$ShortDescription="";
$Description="";

  mysqli_select_db($link, "groups"); 

?>
</div>
<?php
$id = mysql_real_escape_string($_GET['id']);
$out = "SELECT * FROM groups2 WHERE ID = '$id' ";
$result = mysqli_query($link, $out);

$id = mysqli_fetch_array($result);
?>

<div id= "OutShortDescription">
<?php
echo $id['ShortDescription'];
?>
</div>
<div id= "OutDescription">
<?php
echo $id['Description'];
?>
</div>
<div id= "OutStatus">
<?php
echo $id['Status'];
?>
</div>
<div id= "OutDate">
<?php
echo $id['Date'];
?>


<div data-role="footer" data-position="fixed">
<div data-role="navbar">
      <ul>
         <li><a href="#SearchPage" data-transition="slideup" data-icon="search" data-iconpos="top">Search</a></li>
        <li><a href="#NewPage" data-transition="slideup" data-icon="plus" data-iconpos="top">New</a></li>
        <li><a href="#MorePage" data-transition="slideup" data-icon="bars" data-iconpos="top">More</a></li>
      </ul>
    </div><!-- Ende navbar -->

</div>
</body>
</body>
</html>

Answer 1

首先，不要使用mysql_ *方法！请改用PDO或mysqli_*。

下面，我使用PDO粘贴您的示例查询：

array(rowMeans(matrix(unlist(l),, length(l))), dim(l[[1]]))

现在，要获取按钮，您不需要使用jquery：

$dsn = 'mysql:host=localhost;dbname='.$dbname;//$dbName is the name of your database
$user = 'root';
$pass = '123';//use your login information here
$db = new PDO($dsn, $user,$pass);
$query = "SELECT * FROM ToDo1 WHERE id = :id LIMIT 1";
$ps = $db->prepare($query);
$ps->bindParam(':id', $id)
$ps->execute();
$row = $ps->fetch(PDO::FETCH_ASSOC);

另一种选择是使用<?php $path = $row['ID']; $description = $row['ShortDescription']; echo "<form action='your/site/$path'><button type='submit' value='$description'/>$description</form>" ?>：

onclick

<?php $path = $row['ID']; $description = $row['ShortDescription']; echo "<input type=\"button\" onclick=\"location.href='your/site/$path'\" value=\"$description\" />"; ?>之前的\是一个转义符，因此PHP将打印字符"，而不是将其解释为字符串的结尾。

建议：尽量避免混用HTML和PHP，一般来说这是一种不好的做法。

按钮中的MySQL数据库行

1 个答案: