Question

我有一个表格书籍

  NAME  
   A
   B
   C

和另一本书籍分配

ID   ASSIGNMENTTEXT
1     Book.Assigned.To:A
2     Book.Assigned.To:A
3     Book.Assigned.To:B
4     Book.Assigned.To:B
5     Book.Assigned.To:C
6     Book.Assigned.To:A
7     OtherText:A

我想知道为每个人分配了多少本书，例如

我应该

Person     Bookcount
A             3
B             2
C             1

我只想通过Book.Assigned.To:NAME

获取这些行

我尝试过使用子字符串，但我无法解决

谢谢，

艾登

Answer 1

您可以使用内部联接和分组

select a.Name, b.count(*)
from Books a
inner join Booksassignment b on b.ASSIGNMENTTEXT  like concat('%:',  a.NAME)
group by a.Name

Answer 2

如果name列的长度始终为1，则可以如下所示：

SELECT
    B.Name AS Person,
    COUNT(1) Bookcount
FROM
    Books B INNER JOIN 
    Booksassignment  BA ON B.NAME  = BA.RIGHT(ASSIGNMENTTEXT, 1)
GROUP BY
    B.Name

Answer 3

试试这个：

;WITH T AS
(
    SELECT
        Id,
        REPLACE(AssignmentText,SUBSTRING(AssignmentText,0, CHARINDEX(':',AssignmentText,0)+1),'') AS AssignedName
    FROM @tblBooksassignment
)
SELECT
    B.Name,
    COUNT(T.Id) AS 'PersonBookCount'
FROM T
INNER JOIN @tblBooks B ON B.Name=T.AssignedName
GROUP BY B.Name

<强>输出：

Answer 4

CREATE TABLE #T(nAME varchar(25))
INSERT INTO #T
SELECT 'A' UNION ALL
SELECT 'B' UNION ALL
SELECT 'C' 

CREATE TABLE #tt (Id int,Book Varchar(25),Name Varchar(255))
INSERT INTO #tt
SELECT 1,'Book.Assigned','A' UNION ALL
SELECT 2,'Book.Assigned','A' UNION ALL
SELECT 3,'Book.Assigned','B' UNION ALL
SELECT 4,'Book.Assigned','B' UNION ALL
SELECT 5,'Book.Assigned','C' UNION ALL
SELECT 6,'Book.Assigned','A' 


SELECT #tt.Name,COUNT(#tt.Name)  from #tt INNER JOIN #T 
ON #t.Name=#tt.Name 
GROUP BY #tt.Name

Answer 5

我觉得这样的事情会起作用

SELECT B.NAME,
       COUNT( * ) as Bookcount

  FROM Books B

  JOIN Booksassignment BA
    ON B.NAME = SUBSTRING( BA.ASSIGNMENTTEXT, -1 )
   AND BA.ASSIGNMENTTEXT LIKE 'Book.Assigned.To:%'

 GROUP BY B.NAME

Answer 6

如果名称在ASSIGNMENTTEXT列的末尾，则使用right函数

select name, count(*) from Books b
    inner join Booksassignment a on b.name like RIGHT(a.ASSIGNMENTTEXT, 1)
where ASSIGNMENTTEXT like 'Book.Assigned.To:%'
group by name

更新答案 如果你需要第一列是＆＃34; Book.Assigned.To：＆＃34;：

select ASSIGNMENTTEXT, count(*) from Books b
        inner join Booksassignment a on b.name like RIGHT(a.ASSIGNMENTTEXT, 1) 
where ASSIGNMENTTEXT like 'Book.Assigned.To:%'
group by ASSIGNMENTTEXT

例：

with Books as (select * from ( select 'A' as name union select 'B' union select 'C' ) as b )
, Booksassignment as (
    select * from (
        select 1 as iD,  'Book.Assigned.To:A'  ASSIGNMENTTEXT union 
        select 2, 'Book.Assigned.To:A'  union 
        select 3, 'Book.Assigned.To:B'  union 
        select 4, 'Book.Assigned.To:B'  union 
        select 5, 'Book.Assigned.To:C'  union 
        select 6, 'Book.Assigned.To:A'
    ) as c
)
select name, count(b.name) as ASSIGNMENTs from Books b
    inner join Booksassignment a on b.name like RIGHT(a.ASSIGNMENTTEXT, 1) 
group by name

Answer 7

我在Mysql上试了一下：

SELECT CONCAT（SUBSTRING（o.ASSIGNMENTTEXT，-1），＆＃39;＆＃39;，COUNT（ASSIGNMENTTEXT））FROM Booksassignment AS o GROUP BY ASSIGNMENTTEXT < / p>

SQL使用像加入

7 个答案: