我正在制作一个脚本游戏并使用此代码进行多项选择。
while True:
d1a = input ("Do you want to: A) Befriend Fred. B) Be mean to Fred. [A/B]? : ")
if d1a == "A":
print ("You befriend fred. You now have a friend..")
elif d1a == "B":
print ("You angered Fred. He kills you. RIP.")
elif d1a == "Q" :
break
发生这种情况后,如果您键入A或B,它将打印所需的文本然后再次询问您“你想和fred成为朋友吗?”等
答案 0 :(得分:0)
您只需向每个条件添加break
语句:
while True:
d1a = input ("Do you want to: A) Befriend Fred. B) Be mean to Fred. [A/B]? : ")
if d1a == "A":
print ("You befriend fred. You now have a friend..")
break
elif d1a == "B":
print ("You angered Fred. He kills you. RIP.")
break
elif d1a == "Q" :
break
此外,如果您想在一次迭代后离开循环,则不需要循环。但是,我假设你循环直到得到正确的输入,在这种情况下告诉你的播放器输入不正确可能会很好:
while True:
d1a = input ("Do you want to: A) Befriend Fred. B) Be mean to Fred. [A/B]? : ")
if d1a == "A":
print ("You befriend fred. You now have a friend..")
break
elif d1a == "B":
print ("You angered Fred. He kills you. RIP.")
break
else:
print("Incorrect input")