Question

在大多数情况下，我的代码有效。如果您运行它并且输入中没有任何错误，它将按预期工作。如果输入错误，它会显示相应的消息并提示您再次输入，但如果您输入了有效的数字，则会出现错误消息：

Traceback (most recent call last):
  File "C:\Users\Seren\Documents\~School~\MSON Intro Computer Programming\Earthquake.py", line 92, in <module>
    print(r.yourQuakeOutput())
  File "C:\Users\Seren\Documents\~School~\MSON Intro Computer Programming\Earthquake.py", line 49, in yourQuakeOutput
    joules = r.calcJoules()
  File "C:\Users\Seren\Documents\~School~\MSON Intro Computer Programming\Earthquake.py", line 18, in calcJoules
    return 10 ** ((1.5 * self.r) + 4.8)
TypeError: unsupported operand type(s) for *: 'float' and 'NoneType'

我根本不明白这意味着什么，或者如何解决它。我认为它与yourQuakeInput函数有关，但我不确定。有没有人有想法？这是代码本身：

 class Earthquakes:

    def __init__(self, richter):
        self.r = richter

    def calcJoules(self):
        return 10 ** ((1.5 * self.r) + 4.8)

    def calcTNT(self):
        joules = r.calcJoules()
        return joules/(4.184 * 10 ** 9)

    def genericQuake(self):
        joules = r.calcJoules()
        tnt = r.calcTNT()
        return "An earthquake with a %s on the Richter scale is equivalent to %s joules and %s tons of exploded TNT." % (self.r, joules, tnt)

    def specQuake(self, quake):
        joules = r.calcJoules()
        tnt = r.calcTNT()
        return "The %s earthquake, a %s on the Richter scale, was equivalent to %s joules and %s tons of exploded TNT." % (quake, self.r, joules, tnt)

    def yourQuakeInput(self):
        richter = float(input("Your earthquake measures what on the Richter scale?"))
        if richter < 0:
            print("The Richter scale only goes from 0-10. Try again.")
            r.yourQuakeInput()
        elif richter > 10:
            print("The Richter scale only goes from 0-10. Try again.")
            r.yourQuakeInput()
        elif richter >= 0 and richter <= 10:
            return richter
        else:
            print("Invalid input. Try again.")
            r.yourQuakeInput()

    def yourQuakeOutput(self):
        joules = r.calcJoules()
        tnt = r.calcTNT()
        return "Your earthquake, a %s on the Richter scale, is equivalent to %s joules and %s tons of exploded TNT." % (self.r, joules, tnt)

    def __str__(self):
        return "richter=" + str(self.r)

def tryAgain():
    answer = input("Would you like to try again?").lower()
        if answer == "yes":
            pass
        elif answer == "no":
            quit()
        else: 
            print("Invalid input. Try again.")
            tryAgain()

r = Earthquakes (1.0)
print(r.genericQuake())
print("")

r = Earthquakes (5.0)
print(r.genericQuake())
print("")

r = Earthquakes (9.1)
print(r.specQuake("2004 Indonesia"))
print("")

r = Earthquakes (9.2)
print(r.specQuake("1964 Alaska"))
print("")

r = Earthquakes (9.5)
print(r.specQuake("1960 Chile"))
print("")

r = Earthquakes (5.8)
print(r.specQuake("2011 Virginia"))
print("")

while True:
    r = Earthquakes (r.yourQuakeInput())
    print(r.yourQuakeOutput())
    print("")

    tryAgain()

Answer 1

如果您的向导不正确，您似乎缺少返回声明：

if richter < 0:
    print("The Richter scale only goes from 0-10. Try again.")
    return r.yourQuakeInput()
elif richter > 10:
    print("The Richter scale only goes from 0-10. Try again.")
    return r.yourQuakeInput()

关于函数的代码问题（Python）

1 个答案: