Question

@pablo 我似乎陷入了这个循环：

do{
            System.out.println("Voulez-vous saisir d'autres parties? (o/n)");             
            reponse = niveau.nextLine();  // extraction de la dernière ligne 
            if (reponse.toLowerCase().equals("o") == false || reponse.toUpperCase().equals("O") == false || reponse.toLowerCase().equals("n") == false || reponse.toUpperCase().equals("N") == false)  {
            System.out.println("R\u00C9PONSE INVALIDE ! VEUILLEZ ENTRER O OU N.");
            } else {
            validationReponse = true;
            }
        }while(!validationReponse);

谢谢大家的帮助！我能够通过数字答案对问题进行验证，但现在我不知道如何使用“y或n”答案来解决问题。我尝试了这个，但它不起作用：

do{
            System.out.println("Do you want to enter more game scores ? (y/n)");             
            reponse = niveau.nextLine();   
            if (reponse != o || reponse != n) {
            System.out.println("Answer is invalid! Please enter y or n.");
            } else {
                validationReponse = true;
            }
        }while(!validationReponse);

我是初学者。我正在学习我的第一个java课程。在我的代码中，我想为问题添加一个验证：请选择一个游戏级别，你赢了游戏吗？你想要输入更多游戏吗，我需要确保输入是有效的，如果答案无效如果提供，它需要循环回到问题。我不知道该怎么做。请不要在您的答案中使用高级编码。我是初学者班。它需要简单。

String reponse="O";                     

    while (reponse.toLowerCase().equals("o"))      
    { 
                           System.out.println("Please choose your game level :"); 
        System.out.println (" ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");               
        System.out.println (" For Beginner press 1"); 
        System.out.println (" For Advanced press 2"); 
        System.out.println (" For Expert press 3"); 
        System.out.println (" ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");  
        System.out.print (" My choice is : ");

        Niveau = niveau.nextInt();

        if(Niveau == 1){

                int choix1 = 0; 
                nbParties_Facile++;         
                System.out.println("Have you won the game ?");                 
                System.out.println("     Press 1 for YES "); 
                System.out.println("     Press 2 for NO "); 

                choix1 = niveau.nextInt(); 
                niveau.nextLine();  

                    if (choix1 == 1){

                    nbPartiesFaciles_Finies++;
                    tauxReussite_Facile = nbPartiesFaciles_Finies / nbParties_Facile * 100;
                    System.out.println("How many times did you take to complete the grid ?");
                    System.out.println("     Please enter the time in minutes");
                    String afficheur5 = niveau.nextLine();
                    tempsResolution_Facile = (nbPartiesFaciles_Finies * tempsResolution_Facile) + Integer.parseInt(afficheur5) / (nbPartiesFaciles_Finies);
                    }
                    else if (choix1 == 2){
                    tauxReussite_Facile = nbPartiesFaciles_Finies - 1 / nbParties_Facile * 100;
                    }
                    else {
                    //default
                    }
        }

        if(Niveau == 2){

                int choix2 = 0; 
                nbParties_Intermediaire++;            
                System.out.println("Have you won the game ?");                 
                System.out.println("     Press 1 for YES "); 
                System.out.println("     Press 2 for NO "); 

                choix2 = niveau.nextInt();  
                niveau.nextLine();  

                    if (choix2 == 1){

                    nbPartiesIntermediaires_Finies++;
                    tauxReussite_Intermediaire = nbPartiesIntermediaires_Finies / nbParties_Intermediaire * 100;
                    System.out.println("How many times did you take to complete the grid ?");
                    System.out.println("     Please enter the time in minutes");
                    String afficheur7 = niveau.nextLine();
                    tempsResolution_Intermediaire = (nbPartiesIntermediaires_Finies * tempsResolution_Intermediaire) + Integer.parseInt(afficheur7) / (nbPartiesIntermediaires_Finies);
                    }
                    else if (choix2 == 2){
                    tauxReussite_Intermediaire = nbPartiesIntermediaires_Finies - 1 / nbParties_Intermediaire * 100;
                    }
                    else {
                    //default
                    }
        } 

        if(Niveau == 3){

                int choix3 = 0; 
                nbParties_Expert++;            
                System.out.println("Have you won the game ?");                 
                System.out.println("     Press 1 for YES "); 
                System.out.println("     Press 2 for NO "); 

                choix3 = niveau.nextInt();  
                niveau.nextLine();  

                    if (choix3 == 1){

                    nbPartiesExpertes_Finies++;
                    tauxReussite_Expert = nbPartiesExpertes_Finies / nbParties_Expert * 100;
                    System.out.println("How many times did you take to complete the grid ?");
                    System.out.println("     Please enter the time in minutes");
                    String afficheur9 = niveau.nextLine();
                    tempsResolution_Expert = (nbPartiesExpertes_Finies * tempsResolution_Expert) + Integer.parseInt(afficheur9) / (nbPartiesExpertes_Finies);
                    }
                    else if (choix3 == 2){
                    tauxReussite_Expert = nbPartiesExpertes_Finies - 1 / nbParties_Expert * 100;
                    }
                    else {
                    //default
                    }
        } 

        System.out.println("Do you want to enter more games ? (o/n)");             
        reponse = niveau.nextLine();    

    } 

        niveau.close();

Answer 1

让我们以身份为例请选择游戏级别问题

所以你有很多方法可以做到这一点，我会尽量保持简单，因为你是语言的初学者，但目标始终是坚持面向对象的编程。但是，我们可以通过一种简单的方法来实现这一目标。所以你可以有这样一个简单的方法：

private static boolean askForLevel() {
    System.out.println("What is the level you want?");
    String response = scanner.nextLine();
    if (!response.equals("something")) {

        return false;
    }
    askForLevel();
    // More stuff
    return true;
}

Answer 2

如下所示，

do {
        System.out.println("Please choose your game level :"); 
        System.out.println (" ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");               
        System.out.println (" For Beginner press 1"); 
        System.out.println (" For Advanced press 2"); 
        System.out.println (" For Expert press 3"); 
        System.out.println (" ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");  
        System.out.print (" My choice is : ");
        while (!sc.hasNextInt()) {
        System.out.println("That's not a number, Please choose a Number !");
        sc.next();  
    }
    number = sc.nextInt();
} while (number<=3);

在if(number==1)内做与上面相同的事情。

Answer 3

我会使用JOptionPane而不是扫描仪...但这是一个意见问题。既然你是新手，你的老师可能不会直接进入面向对象的编程，这是好的，因为你需要理解基础知识，所以最少使用面向对象的编程：

   //user input
   int level = 0;
   do{
       level = Integer.parseInt(JOptionPane.showInputDialog("Choose the level :").trim());
     }while(level < 1 || level > 3);

    if (level == 1) {
       //your code
    }
    else if(level == 2){
       //your code
    }
    else if(level == 3){
       //your code
    }

你可以用像Pablo建议的私人方法来构建它。

Java为我的代码添加验证

3 个答案: