Question

我几乎没有理解问题：

我有Channel和Lecturer，其中Channel :has_and_belongs_to_many :lecturers。

我希望获得所有频道，其中Lecturer.id是lect.id。

2.3.0 :235 >   Channel.where(:lecturers => { :id => 2 })
  Channel Load (0.1ms)  SELECT "channels".* FROM "channels"  WHERE "lecturers"."id" = 2
SQLite3::SQLException: no such column: lecturers.id: SELECT "channels".* FROM "channels"  WHERE "lecturers"."id" = 2
ActiveRecord::StatementInvalid: SQLite3::SQLException: no such column: lecturers.id: SELECT "channels".* FROM "channels"  WHERE "lecturers"."id" = 2

这不起作用，我觉得我不理解核心概念，因为我可以做到

2.3.0 :231 > Channel.first.lecturer  
=> #<Lecturer id: 2, name: "Albert Einstein">

我错过了什么？

Answer 1

您想要加入表格来执行此查询。见the docs

Channel.joins(:lecturer).where(lecturers: {id: lect.id})

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