Question

我正在使用地形表示围栏，其中1是围栏，0是空格。这是代码：

package assignment_2;

public class Fencing {

public static void main(String[] args) {

    boolean b = true;
    int i;
    int j;
    int[] [] map = 
        {
                {0, 1, 1, 0},
                {1, 2, 1, 1},
                {1, 1, 1, 4},
                {1, 3, 0, 0}
        };
    for (i = 0; i < 4; i++){
        for (j = 0; j < 4; j++){
            if (map[i][j] != 1 && map[i][j] != 0){
                b = false;

                if (b == false){
                    System.out.println("Map does not have the correct format");
                    while (i < 4 && j < 4){
                        System.out.println("--> A value of " + map[i][j] + " was found at " + i + "," + j);
                        i++;
                        j++;

                        }
                    }
                }
                else{
                System.out.println("The map is valid");
                return;

                }   
            }
        }       
    }
}

现在，此代码滚动数组值，如果有值不是1或0，则会将它们报告给用户。如果有错误，则显示所有错误的数字。它的问题是，在它拾取第一个错误后，它会对角滚动通过数组的其余部分并显示这些值而不是显示错误（数字不是1或0）。我认为这与代码的这一部分有关：

while (i < 4 && j < 4){
    System.out.println("--> A value of " + map[i][j] + " was found at " + i + "," + j);
    i++;
    j++;

有谁知道要改变什么？

Answer 1

您可以将程序修改为：

    for (i = 0; i < 4; i++){
        for (j = 0; j < 4; j++){
            if (map[i][j] != 1 && map[i][j] != 0){
               b = false; // greedy approach can break or return here as well
                        System.out.println("--> A value of " + map[i][j] + " was found at " + i + "," + j);

                        }
                    }
               if (b == false){
                    System.out.println("Map does not have the correct format"); }
                else{
                System.out.println("The map is valid"); }

Answer 2

 for (i = 0; i < 4; i++) {
            //set b to true for each Map
            b = true;
            for (j = 0; j < 4; j++) {
                if (map[i][j] != 1 && map[i][j] != 0) {
                        //found incorrect value, set b to false
                        b = false;
                        System.out.println("Map is Invalid :"+map[i][j]);
                    }  
                }
                //If b is true, then ONLY Map is VALID
                if(b) {
                    System.out.println("Map is VALID");
                }
            }

数组值未按预期工作

2 个答案: