Question

我正在使用Spring 1.3.3，我无法使用GET获取嵌入式类的关联对象。它在使用投影时返回URI而不是对象。

   {
      "employeeId": {
        "empId": 4,
        "_links": {
          "address": {
            "href": "http://localhost:8082/address/1"
          },
          "zipcode": {
            "href": "http://localhost:8082/zipcode/2"
          }
        }
      },
      "empId": 4,
      "name": "ap",

    },
    "_links": {
      "self": {
        "href": "http://localhost:8082/employee/com.blah.blah.Employee@64f11498"
      },
      "adNetworkParam": {
        "href": "http://localhost:8082/employee/com.blah.blah.EmployeeId@64f11498{?projection}",
        "templated": true
      },
      "demandSource": {
        "href": "http://localhost:8082/employee/com.blah.blah.EmployeeId@64f11498/address"
      },
      "targetCharacteristic": {
        "href": "http://localhost:8082/employee/com.blah.blah.EmployeeId@64f11498/zipcode"
      }
    }
  }

我的域类如下..

Employee.java

@Entity

@Table(name = "employee")
public class Employee implements Serializable {
    private EmployeeId employeeId;
    private Address address;
    private Zipcode zipcode;
    private int empId;
    private String name;

    //getter
    ...
    @MapsId("address")
    @ManyToOne
    @JoinColumn(name = "address_id")
    public Address getAddress() {
        return address;
    }

    @MapsId("zipcode")
    @ManyToOne
    @JoinColumn(name = "zipcode_id")
    public Zipcode getZipcode() {
        return zipcode;
    }

    // setter
    .....

Address.java

@Entity
@Table(name="address")
public class Address implements Serializable {
    private int id;
    private String streetName;
    private String cityName

Zipcode.java

@Entity
@Table(name = "zipcode")
public class Zipcode implements Serializable {
    @Id
    @GeneratedValue
    private int id;
    private String code;

EmployeeId.java

@Embeddable
public class EmployeeId implements Serializable {
    private Address address;
    private Zipcode zipcode;
    private int empId;

我的投影如下，

@Projection(name = "employeeProjection", types = { Employee.class })
public interface EmployeeProjection {

    Address getAddress();

    Zipcode getZipcode();

    int getEmpId();

    String getName();
}

员工搜索存储库类如下，

@RepositoryRestResource(excerptProjection = EmployeeProjection.class)
interface EmployeeRepository extends CrudRepository<Employee, EmployeeId> {
    List<Employee> findByNameContaining(@Param("name") @RequestParam("name") String name);

    Employee findById(@Param("employeeId") @RequestParam("employeeId") Integer employeeId);

}

如何返回关联对象而不是嵌入类的URI？

请提供您的意见。

Answer 1

您应该在存储库定义中使用摘录。我可以根据您的GET结果猜测，Employee存储库如下：

interface EmployeeRepository extends CrudRepository<Employee, EmployeeId> {}

将其更改为：

@RepositoryRestResource(excerptProjection = EmployeeProjection.class)
interface EmployeeRepository extends CrudRepository<Employee, EmployeeId> {}

这将导致zipCode和地址被内联。请注意，内联资源的链接仍会显示在投影中。

应修改员工模型，并使用嵌入式成员上方的@OneToOne注释进行定义：

@Table(name = "employee")
public class Employee implements Serializable {
    private EmployeeId employeeId;
    @OneToOne
    private Address address;
    @OneToOne
    private Zipcode zipcode;
    private int empId;
    private String name;

您可以在spring doc中阅读更多内容。

如何使用Spring Data Rest在GET调用中获取embeddedId对象

1 个答案: