Question

我一直在尝试使用HttpUrlConnection从一个Android应用程序发送一些信息到一个PHP脚本在线。我对这两个PHP都很新，之前从未使用过HttpUrlConnection，所以我很难理解为什么这不起作用。也没有抛出任何错误。

我的php脚本是

<?php

//get connection details from the app and then connect to db
$db_host = $_POST['db_host'];
$db_user = $_POST['db_user'];
$db_pass = $_POST['db_pass'];
$db_name = $_POST['db_name'];

$con = mysqli_connect($db_host, $db_user, $db_pass, $db_name);

if (!$con) {
    die("Connection failed: " . mysqli_connect_error());
}

$device_group_id = $_POST['device_group_id'];

//create the new device group as a table in the database
$create_table_query = "CREATE TABLE" . $device_group_id . "(
        device_id varchar(24),
        device_alias varchar(24),
        device_longitute int,
        device_latititute int,
        device_group_id varchar(24)
)";

if (mysqli_query($con, $create_table_query)) {
    echo "Table MyGuests created successfully";
} else {
    echo "Error creating table: " . mysqli_error($con);
}

mysqli_close($con);

?>

和Asynctask方法doInBackground（）是

@Override
protected Object doInBackground(Object[] params) {
    String result = "";
    try{
        //get values to pass to the PHP script
        Pair<String, String> dbHost = new Pair<>("db_host", DbConnectionInfo.DB_HOST);
        Pair<String, String> dbUser = new Pair<>("db_user", DbConnectionInfo.DB_USER);
        Pair<String, String> dbPass = new Pair<>("db_pass", DbConnectionInfo.DB_PASS);
        Pair<String, String> dbName = new Pair<>("db_host", DbConnectionInfo.DB_NAME);
        Pair<String, String> deviceGroupId = new Pair<>("device_group_id", "new_device_group");

        URL url = new URL("http://tracme.net16.net/create_device_group.php");
        HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();

        // prepare request
        urlConnection.setRequestMethod("POST");
        urlConnection.setDoInput(true);
        urlConnection.setDoOutput(true);
        urlConnection.setReadTimeout(10000);
        urlConnection.setConnectTimeout(15000);
        urlConnection.setChunkedStreamingMode(0);

        //upload request
        OutputStream outputStream = urlConnection.getOutputStream();
        OutputStreamWriter writer = new OutputStreamWriter(outputStream, "UTF-8");
        writer.write(dbHost.first + "=" + dbHost.second);
        writer.write(dbUser.first + "=" + dbUser.second);
        writer.write(dbPass.first + "=" + dbPass.second);
        writer.write(dbName.first + "=" + dbName.second);
        writer.write(deviceGroupId.first + "=" + deviceGroupId.second);
        writer.close();
        outputStream.close();

        // read response
        BufferedReader in = new BufferedReader(
                new InputStreamReader(urlConnection.getInputStream()));

        String inputLine;
        StringBuffer response = new StringBuffer();
        while ((inputLine = in.readLine()) != null) { response.append(inputLine); }
        in.close();

        result = response.toString();

        // disconnect
        urlConnection.disconnect();

    }catch(MalformedURLException e) {
        Log.e("Malformed URL Exception", "Malformed URL Exception");
    }catch (IOException e) {
        Log.e("IOException", "IOException");
    }

    return result;
}

Answer 1

在您的代码中：

$device_group_id = $_POST['device_group_id'];

//create the new device group as a table in the database
$create_table_query = "CREATE TABLE" . $device_group_id . "(
    device_id varchar(24),
    device_alias varchar(24),
    device_longitute int,
    device_latititute int,
    device_group_id varchar(24)
)";
mysqli_close($con);

您只是创建一个可保存的名称$create_table_query，它只保存查询。没有实际执行查询的代码。在mysqli_close($con);

之前添加此代码

if ($con->query($create_table_query) === TRUE) {
    echo "<br>Table created<br>";
} else {
    echo "<br>Error creating table: " . $con->error. "<br>";
}

Android HttpUrlConnection无法正常工作

1 个答案: