Question

我想要这样，玩家只有一个500-600毫秒的帧来输入1或2.我不知道该怎么做以及我发现的唯一定时器只有

time.sleep(1)

这是我的代码：

        game = 1
    while game == 1:
        play = input(print("'display picture in other window' [1] for right [2] for wrong "))
        if '1' in play:
            print("You shot the Criminal! + 1 point")
            point = point + 1
            row = row + 1
            if row == 3:
                unlock2 = 1
                print ("You gained 2 bonus points!")
                point = point + 2
                row = 0
            if unlock2 == 1:
                point = point + (point/2)
                print ("You gained bonus points!")

        elif '2' in play:
            print("You shot an innocent! Game Over!")
            break

            game = 0

编辑：编辑编辑

Answer 1

执行所需操作的最简单方法是衡量用户响应所需的时间，如下所示：

use Exception;
use Illuminate\Http\Request;
use Illuminate\Auth\AuthenticationException;
use Illuminate\Auth\Access\AuthorizationException;
use Illuminate\Http\Exception\HttpResponseException;
use Symfony\Component\Debug\Exception\FlattenException;
use Illuminate\Database\Eloquent\ModelNotFoundException;
use Symfony\Component\HttpFoundation\Response as SymfonyResponse;

用法：

import time

def respond_in_time(msg, s):
    start = time.time()
    response = input(msg)
    end = time.time()
    print(end-start)
    if end - start > s:
        return False
    else:
        return response

其他代码运行时的Python倒计时

1 个答案: