更多子查询

Question

请问你能解决问题的所在。

MYSQL

Select NameList_name from NameList where NameList.id In  
(Select NameList.id from NameList where id_company = 
(Select company.id From company where company_company Like "XY"))
And
(Select id_NameList from NameListGoods where id_NameListGoodsKind = 
(Select NameListGoodsKind.id from NameListGoodsKind where NameListGoodsKind_NameListGoodsKind LIKE "XX"))
And
(Select id_NameList from NameListStateFrom where id_StateFrom = 
(Select StateFrom.id from StateFrom where StateFrom_state Like "XXX"))
And
(Select id_NameList from NameListStateTo where id_StateTo = 
( Select StateTo.id from StateTo where StateTo_state Like "XYX")); 

这让我回复了＆＃34;＆＃34; SQL Server子查询返回的值超过1个＆＃34;＆＃34; 强文 我想搜索： 从NameList中选择NameList_name，NameList.id 正确的NameList.id外显率 什么从其他子查询返回。

示例：

表名单：

ID   Name    
1    a   
2    b    
3    c    
4    d    
5    e

子查询1：

(Select NameList.id from NameList where id_company = 
(Select company.id From company where company_company Like "XY"))

回复我：数字：1,4,5

子查询2：

(Select id_NameList from NameListGoods where id_NameListGoodsKind = 
(Select NameListGoodsKind.id from NameListGoodsKind where NameListGoodsKind_NameListGoodsKind LIKE "XX"))

回复我：数字2,4,3

子查询3：

(Select id_NameList from NameListStateFrom where id_StateFrom = 
(Select StateFrom.id from StateFrom where StateFrom_state Like "XXX"))

回复我：数字3,4,1

子查询4：

(Select id_NameList from NameListStateTo where id_StateTo = 
(Select StateTo.id from StateTo where StateTo_state Like "XYX"));

回复我：数字5,4,2,1

抬头查询

此结果的穿透数为4.然后我需要显示姓名列表中的名称，其中Namelist.id = 4;

寻求帮助，

Answer 1

SELECT a.id
  FROM (SUBQUERY 1) a
  JOIN (SUBQUERY 2) b
    ON b.id = a.id
  JOIN (SUBQUERY 3) c
    ON c.id = a.id
  JOIN (SUBQUERY 4) d
    ON d.id = a.id;