我们如何在sql中的一列中将多个数据插入到表中

Question

$query= $this->db->query("INSERT INTO _errorlog SET errors = ".$this->db->escape($post['season']).$this->db->escape($post['venue']).$this->db->escape($post['week'])($post['home_team']).$this->db->escape($post['away_team']));

Answer 1

请尝试这个，

$query= $this->db->query("INSERT INTO _errorlog SET errors = ".$this->db->escape($post['season']).$this->db->escape($post['venue']).$this->db->escape($post['week']).$this->db->escape($post['home_team']).$this->db->escape($post['away_team']));

Answer 2

您的数据库查询错误。

在您的数据库查询中检查（$ post ['home_team']），看起来您忘了添加。$ this-＆gt; dbc-＆gt; escape（）。

 $q = INSERT INTO _errorlog SET errors = ".$this->db->escape($post['season']).$this->db->escape($post['venue']).$this->db->escape($post['week'])($post['home_team']).$this->db->escape($post['away_team'])

所以你的查询应该是这个。

  $q = 'INSERT INTO _errorlog SET errors = "'.$this->db->escape($post['season']).$this->db->escape($post['venue']).$this->db->escape($post['week']).$this->db->escape($post['home_team']).$this->db->escape($post['away_team']).'"';