Question

我正在为Absoulute初学者的C编程重写猜测游戏代码＆＃39;使用isdigit（）函数验证用户是否输入了数字。

其余代码在错误检查方面有效;但是当用户输入非数字时，代码进入无限循环。

#include <stdio.h>
#include <stdlib.h>

#define NO 2
#define YES 1

main()

{
    int guessGame;    
    guessGame = 0;

    int iRandomNum = 0;
    int iResponse = 0;

    printf("\n\nWould you like to play \"The Guessing Game\"?\n\n"); 
    printf("\nType '1' for Yes or '2' for No!\n\n"); 
    scanf("%d", &guessGame);

    do{
        if(guessGame == YES){
            iRandomNum = (rand() % 10) + 1;

            printf("\nGuess a number between 1 and 10:\n\n ");
            scanf("%d", &iResponse);

            if(!isdigit(iResponse)){
                printf("\nThank you\n");
                printf("\nYou entered %d\n", iResponse);
                if(iResponse == iRandomNum){
                    printf("\nYou guessed right\n");
                    printf("\nThe correct guess is %d!\n", iRandomNum);
                    printf("\nDo you wish to continue? \n");
                    printf("\nType '1' for Yes or '2' for No!\n\n");
                    scanf("%d", &guessGame);

               } else {
                    printf("\n\nSorry, you guessed wrong\n");
                    printf("\nThe correct guess was %d!\n", iRandomNum);
                    printf("\n\nDo you wish to continue? \n");
                    printf("\nType '1' for Yes or '2' for No!\n\n");
                    scanf("%d", &guessGame);

                }
            }
            else {
                printf("\nYou did not enter a digit\n");
                printf("\n\nPlease enter a number between 1 and 10:\n\n");
                scanf("%d", &iResponse);
            }
        }
        else {
            printf("\nThe window will now close. Try again later!\n");
            exit(0);
        }
    }while(guessGame != NO);
}

Answer 1

由于scanf（）无法读取整数，因此代码进入无限循环。您输入的字符仍保留在键盘缓冲区中。只要字符存在于缓冲区中，就不可能读取整数。 scanf（）只返回每次读为0的项目数。因此，程序不会等待用户输入数据和无限循环结果。

scanf（）返回成功读取的项目数。因此，您可以简单地检查scanf（）的返回值，如果它的1，则scanf（）正确读取整数。

   check = scanf("%d", &iResponse);

   if(check == 1){
        printf("\nThank you\n");
        printf("\nYou entered %d\n", iResponse);

并在输入错误输入时刷新缓冲区

        else {
            while (getchar() != '\n');  //flush the buffer
            printf("\nYou did not enter a digit\n");
            printf("\n\nPlease enter a number between 1 and 10:\n\n");
            //scanf("%d", &iResponse);
        }

这里不需要输入，而循环将继续并在开头提示输入

Answer 2

尝试以字符串的形式输入输入..你也必须比较表格中的输入数字＆＃39; :)

如何让我的代码进入infinte循环？

2 个答案: