输入必须介于100和200之间

Question

我正在创建一个程序，让用户多次输入一个数字，直到所述数字介于100和200之间。如果用户输入字符串或非整数，则会创建错误消息并提示用户再次尝试。目前我遇到了问题：

print("You tried " + guesssesTakenInt + "numbers and " + guessesTakenStr +  
   "non-number to get it right.")

我假设我必须将它变成一个while循环，以便出现以下错误：guessesTakenInt未定义。

##
## a6p2.py
##


def main():
    # this is the code that runs when your program is executed
    guessesTakenInt = 0
    guessesTakenStr = 0
    while True:

        guessesTakenStr += 1
        try:
            userNumber = int(input("Please enter a number between 100 and 200: "))
        except ValueError:
            print("Sorry that is not a number. ")
            continue
        else:
            break

    while userNumber > 0:

        guessesTakenInt += 1ed

        if userNumber > 200:
            userNumber = int(input("This number is too big. Try again: "))
        elif userNumber < 100:
            userNumber = int(input("This number is too low. Try again: "))
        else:
            guessesTakenInt = str(guessesTakenInt)
            guessesTakenStr = str(guessesTakenStr)

                print("That number is just right!")
                print("You tried " + guesssesTakenInt + "numbers and " + guessesTakenStr + " non-number to get it right.")
                break




    return
    print (main())






###############################################################
## DO NOT CHANGE THIS! LEAVE IT AT THE BOTTOM OF YOUR FILE
## calls the main function when this file is run with Python
##
## python stats.py
##
###############################################################
if __name__ == "__main__":
    main()

Answer 1

正如JJJ所述，你有一个错字。但这不是全部，您还有两个不同的show：

1. 用于检查用户是否输入了数字
2. 用于检查数字是否介于100和200之间

这是您需要做的事情：

1. 两个while都应合并为一个。
2. 在将字符串解析为while之前，使用str.isnumeric()来测试字符串是否为NaN。
3. 将int(str)更改为guesssesTakenInt
4. 将guessesTakenInt更改为guessesTakenInt += 1ed
5. 修复缩进

我冒昧地改变你的代码。

guessesTakenInt += 1