如何从张量流中的RNN模型中提取单元状态和隐藏状态?

时间:2016-10-26 21:41:56

标签: python tensorflow lstm

我是TensorFlow的新手,很难理解RNN模块。我试图从LSTM中提取隐藏/单元状态。 对于我的代码,我使用https://github.com/aymericdamien/TensorFlow-Examples中的实现。

# tf Graph input
x = tf.placeholder("float", [None, n_steps, n_input])
y = tf.placeholder("float", [None, n_classes])

# Define weights
weights = {'out': tf.Variable(tf.random_normal([n_hidden, n_classes]))}
biases = {'out': tf.Variable(tf.random_normal([n_classes]))}

def RNN(x, weights, biases):
    # Prepare data shape to match `rnn` function requirements
    # Current data input shape: (batch_size, n_steps, n_input)
    # Required shape: 'n_steps' tensors list of shape (batch_size, n_input)

    # Permuting batch_size and n_steps
    x = tf.transpose(x, [1, 0, 2])
    # Reshaping to (n_steps*batch_size, n_input)
    x = tf.reshape(x, [-1, n_input])
    # Split to get a list of 'n_steps' tensors of shape (batch_size, n_input)
    x = tf.split(0, n_steps, x)

    # Define a lstm cell with tensorflow
    #with tf.variable_scope('RNN'):
    lstm_cell = rnn_cell.BasicLSTMCell(n_hidden, forget_bias=1.0, state_is_tuple=True)

    # Get lstm cell output
        outputs, states = rnn.rnn(lstm_cell, x, dtype=tf.float32)

    # Linear activation, using rnn inner loop last output
    return tf.matmul(outputs[-1], weights['out']) + biases['out'], states

pred, states = RNN(x, weights, biases)

# Define loss and optimizer
cost = tf.reduce_mean(tf.nn.softmax_cross_entropy_with_logits(pred, y))
optimizer = tf.train.AdamOptimizer(learning_rate=learning_rate).minimize(cost)

# Evaluate model
correct_pred = tf.equal(tf.argmax(pred,1), tf.argmax(y,1))
accuracy = tf.reduce_mean(tf.cast(correct_pred, tf.float32))
# Initializing the variables
init = tf.initialize_all_variables()

现在我想提取预测中每个时间步的单元格/隐藏状态。状态存储在形式为(c,h)的LSTMStateTuple中,我可以通过评估print states找到它。但是,尝试调用print states.c.eval()(根据文档应该给出张量states.c中的值),会产生一个错误,指出我的变量没有初始化,即使我在我之后调用它预测某事。这个代码在这里:

# Launch the graph
with tf.Session() as sess:
    sess.run(init)
    step = 1
    # Keep training until reach max iterations
    for v in tf.get_collection(tf.GraphKeys.VARIABLES, scope='RNN'):
        print v.name
    while step * batch_size < training_iters:
        batch_x, batch_y = mnist.train.next_batch(batch_size)
        # Reshape data to get 28 seq of 28 elements
        batch_x = batch_x.reshape((batch_size, n_steps, n_input))
        # Run optimization op (backprop)
        sess.run(optimizer, feed_dict={x: batch_x, y: batch_y})

        print states.c.eval()
        # Calculate batch accuracy
        acc = sess.run(accuracy, feed_dict={x: batch_x, y: batch_y})

        step += 1
    print "Optimization Finished!"

,错误消息是

InvalidArgumentError: You must feed a value for placeholder tensor 'Placeholder' with dtype float
     [[Node: Placeholder = Placeholder[dtype=DT_FLOAT, shape=[], _device="/job:localhost/replica:0/task:0/cpu:0"]()]]

状态在tf.all_variables()中也不可见,只有经过训练的矩阵/偏差张量(如此处所述:Tensorflow: show or save forget gate values in LSTM)。我不想从头开始构建整个LSTM,因为我在states变量中有状态,我只需要调用它。

3 个答案:

答案 0 :(得分:5)

您只需收集states的值,就像收集准确度一样。

我想,pred, states, acc = sess.run(pred, states, accuracy, feed_dict={x: batch_x, y: batch_y})应该可以正常运作。

答案 1 :(得分:5)

关于你的假设的一个评论:“状态”确实只有上一个时间步的“隐藏状态”和“存储单元”的值。

“输出”包含你想要的每个时间步的“隐藏状态”(输出的大小是[batch_size,seq_len,hidden_​​size]。所以我假设你想要“输出”变量,而不是“状态”。 documentation

答案 2 :(得分:3)

我不同意user3480922的回答。对于代码:

outputs, states = rnn.rnn(lstm_cell, x, dtype=tf.float32)

为了能够在预测中提取每个time_step的隐藏状态,您必须使用输出。因为输出具有每个time_step的隐藏状态值。但是,我不确定是否有任何方法可以存储每个time_step的单元格状态值。因为状态元组提供单元格状态值,但仅适用于最后一次time_step。

例如,在以下带有5个time_steps的示例中,输出[4,:,],time_step = 0,...,4具有time_step = 4的隐藏状态值,而状态元组h仅具有time_step = 4的隐藏状态值。状态元组c具有time_step = 4处的单元格值。

  outputs = [[[ 0.0589103 -0.06925126 -0.01531546 0.06108122]
  [ 0.00861215 0.06067181 0.03790079 -0.04296958]
  [ 0.00597713 0.03916606 0.02355802 -0.0277683 ]]

  [[ 0.06252582 -0.07336216 -0.01607122 0.05024602]
  [ 0.05464711 0.03219429 0.06635305 0.00753127]
  [ 0.05385715 0.01259535 0.0524035 0.01696803]]

  [[ 0.0853352 -0.06414541 0.02524283 0.05798233]
  [ 0.10790729 -0.05008117 0.03003334 0.07391824]
  [ 0.10205664 -0.04479517 0.03844892 0.0693808 ]]

  [[ 0.10556188 0.0516542 0.09162509 -0.02726674]
  [ 0.11425048 -0.00211394 0.06025286 0.03575509]
  [ 0.11338984 0.02839304 0.08105748 0.01564003]]

  **[[ 0.10072514 0.14767936 0.12387902 -0.07391471]
  [ 0.10510238 0.06321315 0.08100517 -0.00940042]
  [ 0.10553667 0.0984127 0.10094948 -0.02546882]]**]
  states = LSTMStateTuple(c=array([[ 0.23870754, 0.24315512, 0.20842518, -0.12798975],
  [ 0.23749796, 0.10797793, 0.14181322, -0.01695861],
  [ 0.2413336 , 0.16692916, 0.17559692, -0.0453596 ]], dtype=float32), h=array(**[[ 0.10072514, 0.14767936, 0.12387902, -0.07391471],
  [ 0.10510238, 0.06321315, 0.08100517, -0.00940042],
  [ 0.10553667, 0.0984127 , 0.10094948, -0.02546882]]**, dtype=float32))