我在java中创建了一个包含一列和多行的表,我还有一个String行,我想在我的字符串行中导入我的值列表: 我运行了我的代码,结果如下:
begining of line [item1] end of line
begining of line [item2] end of line
begining of line [item3] end of line
begining of line [item4] end of line
但我正在寻找这样的结果:
begining of line [item1],
[item2],
[item3],
[item4] end of line
这是我的代码:
DefaultTableModel model = (DefaultTableModel) jTable1.getModel();
for (int i=0;i<model.getRowCount();i++){
String b = " ["+(jTable1.getValueAt(i,0)).toString()+"] ";
String text="begining of line"+b+"end of line";
System.out.println(text);
}
我是java新手感谢
答案 0 :(得分:0)
你可以在for循环之前启动文本for循环,在for循环中添加项目到文本,并在for循环之后添加“end of line”。您可以使用+运算符来连接字符串,或者如果您想要高效,可以使用Stringbuilder类。
答案 1 :(得分:0)
试试这段代码:
String beginning= "beginning of line";
String emptySpaces = new String(new char[begining.length()]).replace("\0", " "); // Create empty spaces with the same length of the begining sentence
StringBuilder builder = new StringBuilder();
for (int i = 0; i < model.getRowCount(); i++) {
final String first = (i == 0) ? begining : emptySpaces;
builder.append(first).append(" [").append(jTable1.getValueAt(i,0).toString()).append("]");
final String last = (i == model.getRowCount() - 1) ? " end of line" : ",\n";
builder.append(last);
}
System.out.println(builder.toString());
我使用字符串构建器来避免字符串创建性能问题
它会显示预期的结果
beginning of line [item1],
[item2],
[item3],
[item4],
[item5] end of line