Question

我有一个像这样的数组

[
  {
    item_guid: "57e7a1cd6a3f3669dc03db58"
    quantity:3
  },
  {
    item_guid: "57e77b06e0566d496b51fed5"
    quantity:3
  },
  {
    item_guid: "57e7a1cd6a3f3669dc03db58"
    quantity:3
   },
  {
    item_guid: "57e77b06e0566d496b51fed5"
    quantity:3
  }
]

我想从这里将类似的item_guid合并到一个对象中，数量总结如下

[
  {
    item_guid: "57e7a1cd6a3f3669dc03db58"
    quantity:6
   },
  {
    item_guid: "57e77b06e0566d496b51fed5"
    quantity:6
  }
]

我知道这可以实现一些循环，而不是寻找使用lodash或EcmaScript2015代码的解决方案来让我们的生活更轻松

Answer 1

一种简单的方法：

循环数据并创建一个对象，其中key将是唯一ID，其值将是数量。然后循环回对象的键并创建对象。

var data = [{ item_guid: "57e7a1cd6a3f3669dc03db58", quantity: 3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity: 3 }, { item_guid: "57e7a1cd6a3f3669dc03db58", quantity: 3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity: 3 }],

var r = {};
data.forEach(function(o){
  r[o.item_guid] = (r[o.item_guid] || 0) + o.quantity;
})

var result = Object.keys(r).map(function(k){
  return { item_guid: k, quantity: r[k] }
});
console.log(result)

Answer 2

普通Javascript中的解决方案，其中包含item_guid的哈希表。

＆＃13;

var data = [{ item_guid: "57e7a1cd6a3f3669dc03db58", quantity: 3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity: 3 }, { item_guid: "57e7a1cd6a3f3669dc03db58", quantity: 3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity: 3 }],
    grouped = data.reduce(function (hash) {
        return function (r, a) {
            (hash[a.item_guid] = hash[a.item_guid] || r[r.push({ item_guid: a.item_guid, quantity: 0 }) - 1]).quantity += a.quantity;
            return r;
        };
    }(Object.create(null)), []);

console.log(grouped);

＆＃13;

ES6

＆＃13;

var data = [{ item_guid: "57e7a1cd6a3f3669dc03db58", quantity: 3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity: 3 }, { item_guid: "57e7a1cd6a3f3669dc03db58", quantity: 3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity: 3 }],
    grouped = data.reduce((map => (r, a) => {
        map.set(a.item_guid, map.get(a.item_guid) || r[r.push({ item_guid: a.item_guid, quantity: 0 }) - 1]);
        map.get(a.item_guid).quantity += a.quantity;
        return r;
    })(new Map), []);

console.log(grouped);

＆＃13;

Answer 3

你可以

按item_guid
对结果组中的对象求和
以您想要的格式转换这些组

这样的事情：

var result = _.chain(data)
    .groupBy('item_guid')
    .map(function(objects, guid) {
        return {
            item_guid: guid, 
            quantity: _.sumBy(objects, 'quantity')
        };
    })
    .value();

和演示

var data = [
  {
    item_guid: "57e7a1cd6a3f3669dc03db58",
    quantity:3
  },
  {
    item_guid: "57e77b06e0566d496b51fed5",
    quantity:3
  },
  {
    item_guid: "57e7a1cd6a3f3669dc03db58",
    quantity:3
   },
  {
    item_guid: "57e77b06e0566d496b51fed5",
    quantity:3
  }
];


var result = _.chain(data)
    .groupBy('item_guid')
    .map(function(objects, guid) {
        return {
            item_guid: guid, 
            quantity: _.sumBy(objects, 'quantity')
        };
    })
    .value();
  
  console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.16.4/lodash.min.js"></script>

Answer 4

var groupedItems = [];

var totalItems = [{item_guid: "57e7a1cd6a3f3669dc03db58", quantity:3},{item_guid: "57e77b06e0566d496b51fed5",quantity:3}, { item_guid: "57e7a1cd6a3f3669dc03db58", quantity:3 }, { item_guid: "57e77b06e0566d496b51fed5", quantity:3}];

totalItems.forEach((e) => {
  if (groupedItems.findIndex(x => x.item_guid === e.item_guid) < 0) {
    let totalQuantity = totalItems
                       .filter(x => x.item_guid === e.item_guid)
                       .map(x => x.quantity)
                       .reduce(function(a, b) { return a + b;});

    groupedItems.push({item_guid: e.item_guid, quantity: totalQuantity})
  }
})

console.log(groupedItems);

合并对象＆amp;总结单个属性javascript

4 个答案: