Question

我需要在java中读取文件xml，xmd文档如下所示：

 <?xml version="1.0" encoding="UTF-8"?>
  <Provider>
       <Invoice>256848</Invoice>
      <InvoiceType>Paper</InvoiceType>
      <Phone>0554334434</Phone>
      <InvoiceDate>20091213</InvoiceDate>   
     <CustomerRequest>
       <Article>
         <ArticleCode>PE4</ArticleCode>
        <ArticleDescription>Pen</ArticleDescription>
        <DeliveryDate>20091231</DeliveryDate>
         <Price>150</Price>
       </Article>
    </CustomerRequest>   
    <CustomerInfo>
      <CustomerID>6901</CustomerID>
      <CustomerAddress> Houghton Street</CustomerAddress>
      <CustomerCity>London</CustomerCity>
   </CustomerInfo>

 </Provider>

问题是文档的内容可以改变，通过包含其他标签和许多可以具有随机级别的嵌套标签，是否有办法获得文档的所有标签和值以动态方式而不指定标签名称？感谢

Answer 1

由于XML是作为树构建的，因此您需要使用递归：

假设这是您的主要课程：

public static void main(String[] args) throws SAXException, IOException,
        ParserConfigurationException, TransformerException {

    DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory
        .newInstance();
    DocumentBuilder doc = docBuilderFactory.newDocumentBuilder();
    Document document = doc.parse(new File("doc.xml"));
    childRecusrsion(document.getDocumentElement());
}

这就是递归：

  public static void childRecusrsion(Node node) {
        // do something with the current node instead of System.out
        System.out.println(node.getNodeName());

        NodeList nodeList = node.getChildNodes(); //gets the child nodes that you need
        for (int i = 0; i < nodeList.getLength(); i++) {
            Node currentNode = nodeList.item(i);
            if (currentNode.getNodeType() == Node.ELEMENT_NODE) {
                //call the recursion
                childRecusrsion(currentNode);
            }
        }
    }

如何在没有tagName

1 个答案: