大家。我被困在我正在研究的这个项目上。我希望能够从android库中上传图像，将该图像编码为base64字符串并发送到PHP Web服务，作为get变量，然后从另一端解码图像并按照我的意愿处理它。 / p>
到目前为止，我可以从图库中选择图像，甚至编码为base64字符串并存储在Android首选项中。
问题是，我认为并非所有字符串都被发送到PHP服务（有些被截断）。
为什么我这么认为？我的Log.d在不同位置转储时向我显示了不同的字符串。
获取图像和编码的代码是： -
private void galleryIntent()
{
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Please select a file"),1);
}
private String onSelectFromGalleryResult (Intent data) {
if (data != null) {
try {
bitmap = MediaStore.Images.Media.getBitmap(getContext().getContentResolver() , data.getData()) ;
} catch (IOException e) {
e.printStackTrace();
}
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream() ;
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, byteArrayOutputStream) ;
byte[] imageBytes = byteArrayOutputStream.toByteArray() ;
Log.d ("Selected Image Gallery" , Base64.encodeToString(imageBytes, Base64.DEFAULT)) ;
return Base64.encodeToString (imageBytes, Base64.DEFAULT) ;
} else {
return null ;
}
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
SharedPreferences sharedPreferences = getContext().getSharedPreferences("MyOnActivityResultPref" , Context.MODE_PRIVATE);
SharedPreferences.Editor editor = sharedPreferences.edit() ;
if (resultCode == Activity.RESULT_OK) {
if (requestCode == 1) {
/*Here we handle the image gotten from the gallery*/
String encodedGalleryImage = onSelectFromGalleryResult(data);
editor.putString("userEncodedGalleryImage" , encodedGalleryImage);
} else if (requestCode == 0) {
/*Here we handle the image that was take using the camera*/
}
editor.apply();
}
}
这里我们称之为asynctask类
private void callAsynctask () {
SharedPreferences sp = getContext().getSharedPreferences("MyOnActivityResultPref" , Context.MODE_PRIVATE);
String userQuestionAttachement = sp.getString("userEncodedGalleryImage" , "") ;
Log.d("callingEncodedImage" , userQuestionAttachement) ;
}
我遇到的问题是来自Log.d的日志（＆＃34;选择图像库＆＃34;，Base64.encodeToString（imageBytes，Base64.DEFAULT））;与Log.d不同（＆＃34; callingEncodedImage＆＃34;，userQuestionAttachement）;
两者都有相同的开头但不同的结局。我希望看到相同的角色。
有人可以帮我解决一下吗？
答案 0 :(得分：1)
在Android中，
new UploadFileAsync().execute("");
private class UploadFileAsync extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
try {
String sourceFileUri = "/mnt/sdcard/abc.png";
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (sourceFile.isFile()) {
try {
String upLoadServerUri = "http://website.com/abc.php?";
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(
sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE",
"multipart/form-data");
conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("bill", sourceFileUri);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"bill\";filename=\""
+ sourceFileUri + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math
.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0,
bufferSize);
}
// send multipart form data necesssary after file
// data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens
+ lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn
.getResponseMessage();
if (serverResponseCode == 200) {
// messageText.setText(msg);
//Toast.makeText(ctx, "File Upload Complete.",
// Toast.LENGTH_SHORT).show();
// recursiveDelete(mDirectory1);
}
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
} catch (Exception e) {
// dialog.dismiss();
e.printStackTrace();
}
// dialog.dismiss();
} // End else block
} catch (Exception ex) {
// dialog.dismiss();
ex.printStackTrace();
}
return "Executed";
}
@Override
protected void onPostExecute(String result) {
}
@Override
protected void onPreExecute() {
}
@Override
protected void onProgressUpdate(Void... values) {
}
}
在Php中，
<?php
if (is_uploaded_file($_FILES['bill']['tmp_name'])) {
$uploads_dir = './';
$tmp_name = $_FILES['bill']['tmp_name'];
$pic_name = $_FILES['bill']['name'];
move_uploaded_file($tmp_name, $uploads_dir.$pic_name);
}
else{
echo "File not uploaded successfully.";
}
?>
答案 1 :(得分：0)
要使用 Multipart 上传图片，请按照以下步骤操作：
下载httpmime.jar文件并将其添加到 libs 文件夹中。
下载http client.jar文件并将其添加到 libs 文件夹中。
从后台线程或AsyncTask调用以下方法。
public void executeMultipartPost() throws Exception {
try {
ByteArrayOutputStream bos = new ByteArrayOutputStream();
bm.compress(CompressFormat.JPEG, 75, bos);
byte[] data = bos.toByteArray();
HttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost(
"YOUR SERVER URL");
ByteArrayBody bab = new ByteArrayBody(data, "YOUR IMAGE.JPG");
MultipartEntity reqEntity = new MultipartEntity(
HttpMultipartMode.BROWSER_COMPATIBLE);
reqEntity.addPart("IMAGE", bab);
postRequest.setEntity(reqEntity);
HttpResponse response = httpClient.execute(postRequest);
BufferedReader reader = new BufferedReader(new InputStreamReader(
response.getEntity().getContent(), "UTF-8"));
String sResponse;
StringBuilder s = new StringBuilder();
while ((sResponse = reader.readLine()) != null) {
s = s.append(sResponse);
}
System.out.println("Response: " + s);
} catch (Exception e) {
// handle exception here
Log.e(e.getClass().getName(), e.getMessage());
}
}