Question

我有一个通过API获得的JSONObject。就像这样：

    {
     "wash_method": 305,
     "fragrance": 1156,
     "sweater_type": 260,
     "dial_color": 66475,
     "charger_type": 2581,
     "pen_drives_interface": 563,
      "watches_type": 66475,
      "processor": 3270,
      "frame_material": 1211,
      "dial_shape": 66475,
      "os": 3308
     }

我想根据值对此进行排序，以获得如下结果：

    {
     "dial_shape": 66475,
     "dial_color": 66475,
     "watches_type": 66475,
      "os": 3308,
      "processor": 3270,
      "charger_type": 2581,
      "frame_material": 1211,
      "fragrance": 1156,
      "pen_drives_interface": 563,
     "wash_method": 305,
     "sweater_type": 260,      
     }

正如您所看到的，前三项具有相似的价值，因此可以以任何方式进行排列我怎样才能做到这一点？（有没有办法以最小的复杂性做到这一点？）

Answer 1

以下是您的问题的解决方案。我希望这会有所帮助。

<!DOCTYPE html>
<html lang="en">
<head>
  <title>Bootstrap Example</title>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width, initial-scale=1">
  <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
  <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</head>
<body>

<div class="container">
  <h2>Image</h2>
  <p>The .img-responsive class makes the image scale nicely to the parent element (resize the browser window to see the effect):</p>
  <img class="img-responsive" src="http://placehold.it/350x150" alt="Chania" width="460" height="345">
</div>

</body>
</html>

}

Answer 2

尝试实施此

int[] col = YourClass.getTableSortedColumns(jTable);
    for(int i = 0;i<col.length;i++){
        if(col[i]>=0){
            String orientation = "";
            switch(YourClass.getTableSortedOrientation(jTable, col[i])){
                case 1:
                    orientation = "Ascending";
                    break;
                case 0:
                    orientation = "Unsorted";
                    break;
                case -1:
                    orientation = "Descending";
                    break;
            }
            System.out.println("index "+col[i]+" "+orientation);
        }
    }

<强>更新

public class SomeClass {

    /**
     * Sorts the given JSONObject
     *
     * @param jsonObject
     * @return jsonObject sorted in descending order
     * @throws JSONException
     */
    public JSONObject sortJSONObject(JSONObject jsonObject) throws JSONException {

        ArrayList<SomeChildClass> alstSomeChildClass = new ArrayList<>();

        Iterator<String> keys = jsonObject.keys();

        while (keys.hasNext()) {
            SomeChildClass someChildClass = new SomeChildClass();
            someChildClass.key = keys.next();
            someChildClass.value = jsonObject.getString(someChildClass.key);
            alstSomeChildClass.add(someChildClass);
        }

        // Sort the Collection
        Collections.sort(alstSomeChildClass);

        JSONObject sortedJsonObject = new JSONObject();
        for (SomeChildClass someChildClass : alstSomeChildClass)
            sortedJsonObject.put(someChildClass.key, someChildClass.value);

        return sortedJsonObject;
    }

    private class SomeChildClass implements Comparable<SomeChildClass> {

        private String key;
        private String value;

        @Override
        public int compareTo(@NonNull SomeChildClass target) {

            int currentVal = Integer.parseInt(value);
            int targetVal = Integer.parseInt(target.value);

            return (currentVal < targetVal) ? 1 : ((currentVal == targetVal) ? 0 : -1);
        }
    }
}

JAVA按降序排序JSONObject（String，Int）

2 个答案: