Question

我在数据库中有一个包含2列的表，id（自动增量）和名称。

id|name
--|----
1 |John
2 |Jeff
3 |Jack

我希望在我的网页中显示最后一个插入名称，以便我echo "The last person is $last_name";

我尝试使用以下命令检索数据，但它什么也没显示。

$last_name = mysqli_query($conn, 'SELECT name FROM namelist ORDER BY id DESC LIMIT 1')

有人请帮忙吗？谢谢。

Answer 1

试试这个......

如果是程序

$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
mysqli_query($conn, $query);
mysqli_insert_id($conn)

如果面向对象

$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
$mysqli->query($query);
$mysqli->insert_id

更多信息...... http://php.net/manual/en/mysqli.insert-id.php

Answer 2

尝试这个

$last_name = mysqli_query($conn, 'SELECT name FROM namelist ORDER BY id DESC LIMIT 1')

if (mysqli_num_rows($last_name) > 0) {
// output data of row
    while($row = mysqli_fetch_assoc($last_name)) {
        echo "Name: " . $row["name"];
    }
} else {
    echo "0 results";
}

Answer 3

mysqli_query($conn, 'SELECT name FROM namelist ORDER BY id DESC LIMIT 0,1')

如何使用PHP显示特定列

3 个答案: